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2 years ago

Y = -7/6x + 10 slope = y-intercept =

Mathematics

1 answer:

arsen [322]2 years ago

4 0

Answer:

the answer is actualy 12

Step-by-step explanation:

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In a box there are three types of chocolate. there are 6 plain chocolate 8 milk chocolate and 10 white chocolate. Deon takes 2 c

olchik [2.2K]

Step-by-step explanation:

1 plain chocolate and 1milk chocolate
1 plain chocolate and 1 white chocolate
1 milk chocolate and 1 white chocolate

<h3>we have to it like that only right??</h3>

8 0

2 years ago

Plzzzzzzzzzzz answerrrrrrrrrrrrrrrr i need it asap

saul85 [17]

Answer: 120

1.2

If Maxine is correct, then she spent

1.2

times the hours she did homework than last week.

⋅

1.2

18.0

15 hours

⋅

1.2

18.0 hours

18 hours

This means that Maxine is correct.

HOPE THIS HELPS

6 0

2 years ago

A salesman travelled 2/5 of his journey before lunch and 3/8 of his journey after lunch.

AysviL [449]

2/5+3/8= 31/40 therefore he still has 9/40 to go.
to get this you multiply the two denominators together
5x8=40 which is your denominator
then you cross multiply the two numerators
2x8=16
3x5=15
to get the final
15/40+16/40=31/40
and you are left with 9/40

7 0

3 years ago

F(x)

mina [271]

a) Since both limits are <em>distinct</em> and do not exist, we conclude that x = - 1 is not part of the domain of the <em>rational</em> function.

b) The function $f(x) = \frac{x}{x^{2}+ x}$ is equivalent to the function $g(x) = \frac{1}{x + 1}$ .

<h3>How to determine whether a limit exists or not</h3>

According to theory of limits, a function f(x) exists for x = a if and only if $\lim_{x\to a^{-}} f(x) = \lim_{x \to a^{+}} f(x)$ . This criterion is commonly used to prove continuity of functions.

<em>Rational</em> functions are not continuous for all value of x, as there are x-values that make denominator equal to 0. Based on the figure given below, we have the following <em>lateral</em> limits:

$\lim_{x \to -1^{-}} \frac{x}{x^{2}+x} = - \infty$

$\lim_{x \to -1^{+}} \frac{x}{x^{2}+x} = + \infty$

Since both limits are <em>distinct</em> and do not exist, we conclude that x = - 1 is not part of the domain of the <em>rational</em> function.

In addition, we can simplify the function by <em>algebra</em> properties:

$\frac{x}{x^{2}+ x} = \frac{x}{x\cdot (x + 1)} = \frac{1}{x + 1}$

$g(x) = \frac{1}{x + 1}$

The function $f(x) = \frac{x}{x^{2}+ x}$ is equivalent to the function $g(x) = \frac{1}{x + 1}$ .

To learn more on lateral limits: brainly.com/question/21783151

#SPJ1

7 0

1 year ago

PLS SOMEONE HELP ME!! ASAP I HAVE NO CLUE WHAT IM DOING!!

Rom4ik [11]

Ok so first you should suck ur m0ms d1ck
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4 0

3 years ago