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Leviafan [203]
3 years ago
8

The school newspaper surveyed 100 commuter students and asked two questions. First, students were asked how many courses they we

re currently enrolled in. Second, the commuter students were asked to estimate how long it took them to drive to campus. Considering these two variables, number of courses would best be considered a _________ variable and drive time would be considered a _________ variable.
Mathematics
1 answer:
Vladimir79 [104]3 years ago
7 0

Answer:

Number of courses would best be considered a discrete variable and drive time would be considered a continuous variable.

Step-by-step explanation:

Discrete variable:

Countable amounts(0, 1, 2, 3,...)

Continuous variables:

Can be decimal values.

In this question:

The number of courses is a countable amount(0,1,2,3,...), you cant take half a course, for example, so it is discrete. Otherwise, drive time accepts half minutes, for example, 10.5 minutes, so is continuous.

Number of courses would best be considered a discrete variable and drive time would be considered a continuous variable.

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A rhombus ABCD has AB = 10 and m∠A = 60°. Find the lengths of the diagonals of ABCD.
melisa1 [442]
Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus

First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°. 

Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.

For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.

\overline{OB}:\overline{AB} = 1:2
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Similarly, we have

\overline{AO}:\overline{AB} = \sqrt{3}:2
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\overline{AO} = \frac{\sqrt{3}}{2}(10) = 5\sqrt{3}

Now, to find the lengths of the diagonals, 

\overline{AD} = 2(\overline{AO}) = 10\sqrt{3}
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So, the lengths of the diagonals are 10 and 10√3.

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8 0
3 years ago
If g(x) = 3(x + 10), what is the value of the<br> function when x = -8?<br> O<br> -8<br> -2<br> 24
Gala2k [10]

Answer:

6 which is none of your answers.

Are you sure your function is right?

Is value to plug in x=-8?

Step-by-step explanation:

To find the value of the function at x=-8, you replace x with -8 in the function.

g(x)=3(x+10)

g(-8)=3(-8+10)

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7 0
3 years ago
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Answer:

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Step-by-step explanation:

In this question, we are concerned with calculating the time taken for a loan om an interest to be paid back

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I don't know I'm sorry
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