Answer:
haha sorry taaga wala talaga ehh kala ko nga d na ako makaka balik dto sa acc ko haha(╥﹏╥)
Answer:
Number of fish in 2006 = 845 fishes (Approx.)
Step-by-step explanation:
Given;
Number of fish in 2000 = 1,150 fishes
Decreasing rate = 5% per year
Find:
Number of fish in 2006
Computation:
Exponential decay function:
F = P[1-r]ⁿ
Number of year = 2006 - 2000
Number of year = 6 year
Number of fish in 2006 = 1,150[1-5%]⁶
Number of fish in 2006 = 1,150[1-0.05]⁶
Number of fish in 2006 = 1,150[0.95]⁶
Number of fish in 2006 = 1,150[0.735]
Number of fish in 2006 = 845.25
Number of fish in 2006 = 845 fishes (Approx.)
Answer:
$0.80
Step-by-step explanation:
$16.40 ÷ 20.5 = 0.80
You can check your work by doing :
20.5 cm of wire × $0.80 = $16.40
Answer:
y= 3x +9
Step-by-step explanation:
m= 3
The y-intercept of the line that passes through the given point (0,9) is
9 = 0(3) + b
b= 9
The equation of the line that passes through the given point (0,9) is
y =mx +b
y = 3x +9