343=343=343
I am pretty sure this is the answer to the problem
-- The probability of rolling a 22 is zero. That result is impossible, because the sides are labeled with single digits 1 through 6 . Since 22 is not printed anywhere on the cube, it can never come up.
-- The probability of rolling a<em> 2</em> , however, is <em> 1/6</em> . <em>(B)</em>
<em></em>
The -probability of rolling something you want is always
<em>(the number of different possible results that you like) </em>
divided by
<em>(the total number of different possible results)</em>
Sample space = HHH, HHT, HTH, THH, TTT, TTH, THT, HTT (8 possibilities)
Desirable outcomes = TTH, THT, TTH (3 possibilities)
Required probability = 3/8
Given the numbers on the computer 123 is shown very complicated. Well it’s not given all the numbers and mind thinking if u add formula 1 that shows that I have no idea what to tell you and ur stuck
Hola! Intente resolverlo pero solo hice la primera por mi tiempo ahorita mismo y era:
f(0)=1
Toda la ecuación
