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marta [7]
3 years ago
11

Find the product. Simplify.

Mathematics
2 answers:
rusak2 [61]3 years ago
8 0
Number 5, right ? 
36: 1,2,3,4,9,12,18,36
54:1,2,3,6,9,18,27,54
GCF of 36 and 54 : 18


PtichkaEL [24]3 years ago
3 0
10/18. simplified is 5/9
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The half-life of the radioactive elements unobtanium -41 is 5 seconds. If 48 grams of unobtanium -41 are initially present, how
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Answer:

the remaining mass of unobtanium -41 after a 5 seconds, 10 seconds, 15 seconds and 20 seconds is 24 gr, 12 gr , 5.33 gr and 3 gr respectively

Step-by-step explanation:

the equation that governs the remaining mass m of unobtanium -41 after a time t is

m=m₀*2^(-t/T) , where t is in seconds ,m₀ represents initial mass and T=half-life

Therefore

a) for t=5 s

m=48 gr*2^(-t/5 s) = 48 gr*2^(-5 s/5 s) = 48 gr/2 = 24 gr

b)  for t=10 s

m=48 gr*2^(-t/5 s) = 48 gr*2^(-10 s/5 s) = 48 gr/4 = 12 gr

b)  for t=15 s

m=48 gr*2^(-t/5 s) = 48 gr*2^(-15 s/5 s) = 48 gr/9 = 5.33 gr

b)  for t=20 s

m=48 gr*2^(-t/5 s) = 48 gr*2^(-20 s/5 s) = 48 gr/16 = 3 gr

thus the remaining mass of unobtanium -41 after a 5 seconds, 10 seconds, 15 seconds and 20 seconds is 24 gr, 12 gr , 5.33 gr and 3 gr respectively

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