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3 years ago

13

If X = {−1, 0, 2} and Y = {1, 2, 5}, find X ∪ Y.

2 answers:

Irina18 [472]3 years ago

5 0

yo sup??

as mentioned earlier XUY is simply the summation of all the unique elements of X and Y

S=XUY

={-1,0,1,2,5}

Therefore your answer is option 1 ie

1.{-1,0,1,2,5}

Hope this helps.

andrey2020 [161]3 years ago

4 0

Answer:

Step-by-step explanation:

If X = {−1, 0, 2} and Y = {1, 2, 5}

X ∪ Y is the combination of all the element in X and Y without repetition

X U Y = {-1, 0, 1, 2, 5}

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A jar at the fishing shop holds 72 worms. A cup holds 8 worms. How many times

Anettt [7]

Answer:

9 times. 72/8=t or 72=8t.

Explanation:

I'm afraid the answer choices are slightly mixed up, but acceptable answers would probably include 72/8=t or 72=8t. Simply put the two numbers into a fraction (72/8) to get how many times larger or smaller the thing is. In this case, it would be 9 times as many worms.

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3 years ago

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4 1/2 + 1 + 2 + 1 1/2 + 4 + 1/2

mafiozo [28]

Your answer would be 17 1/2

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3 years ago

Write an exponential function in the form y=ab^xy=ab x that goes through points (0, 20)(0,20) and (6, 1280)(6,1280).

Phoenix [80]

Answer:

$y=20(2)^x$

Step-by-step explanation:

We want to write an exponential function that goes through the points (0, 20) and (6, 1280).

The standard exponential function is given by:

$y=ab^x$

The point (0, 20) tells us that <em>y</em> = 20 when <em>x</em> = 0. Hence:

$20=a(b)^0$

Simplify:

$20=a(1)\Rightarrow a=20$

So, our exponential function is now:

$y=20(b)^x$

Next, the point (6, 1280) tells us that <em>y</em> = 1280 when <em>x</em> = 6. Thus:

$1280=20(b)^6$

Solve for <em>b</em>. Divide both sides by 20:

$64=b^6$

Therefore:

$b=\sqrt[6]{64}=2$

Hence, our function is:

$y=20(2)^x$

8 0

2 years ago

I cant figure this one out at all

eduard

Answer:

a. 2^(x-2) = g^(-1)(x)

b. A, B, D

Step-by-step explanation:

the phrasing attached in the image is flagged as inappropriate, so i will be replacing it with g(x) and its inverse with g^(-1)(x)

1. replace g(x) with y and solve for x

y = log₂(x) + 2

subtract 2 from both sides to isolate the x and its log

y - 2 = log₂(x)

this text is replaced by the second image -- it was marked as inappropriate

thus, 2^(y-2) = x

replace x with g^(-1)(x) and y with x

2^(x-2) = g^(-1)(x)

2. plug this in to points A, B, C, D, E, and F

A: (2,1)

plug 2 in for x

2^(2-2) = 2⁰ = 1 so this works

B: (4, 4)

2^(4-2) = 2²= 4 so this works

C: (9, 3)

2^(9-2) = 2⁷ = 128 ≠ 3 so this doesn't work

(5, 8)

2^(5-2) = 2³ = 8 so this works

E: (3, 5)

2^(3-2) = 2¹ = 2 ≠ 5 so this doesn't work

F: (8, 5)

2^(8-2) = 2⁶ = 64 ≠ 5 so this doesn't work

4 0

2 years ago

5. Which equation is of a circle that has a center at

Basile [38]

Answer:

$\large\boxed{D.\ (x-3)^2+(y+2)^2=81}$

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the center at (3, -2) and the radius r = 9. Substitute:

$(x-3)^2+(y-(-2))^2=9^2\\\\(x-3)^2+(y+2)^2=81$

5 0

2 years ago