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Nady [450]
4 years ago
13

If X = {−1, 0, 2} and Y = {1, 2, 5}, find X ∪ Y.

Mathematics
2 answers:
Irina18 [472]4 years ago
5 0

yo sup??

as mentioned earlier XUY is simply the summation of all the unique elements of X and Y

S=XUY

={-1,0,1,2,5}

Therefore your answer is option 1 ie

1.{-1,0,1,2,5}

Hope this helps.

andrey2020 [161]4 years ago
4 0

Answer:

Step-by-step explanation:

If X = {−1, 0, 2} and Y = {1, 2, 5}

X ∪ Y is the combination of all the element in X and Y without repetition

X U Y = {-1, 0, 1, 2, 5}

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Find the perimeter of a regular pentagon with sides of (3x + 5).
kotegsom [21]

Answer:

  5(3x + 5)   or   15x + 25

Step-by-step explanation:

A regular pentagon has 5 sides of equal length. The perimeter is the sum of the lengths of those sides. We can use multiplication to find the sum of 5 of the same value:

  P = 5(3x +5)

Perhaps you want it expanded. Using the distributive property, we multiply each term in parentheses by 5:

  P = 15x + 25

4 0
4 years ago
Please Help!! 10 Points!! brainliest answer
MaRussiya [10]

Answer:

The answer is d because they are similar

Step-by-step explanation:

5 0
3 years ago
If 2a =-10 then -6a=
suter [353]

If 2a = -10, that means a = -5 Because 2(-5) makes -10.

Thus, -6(-5) = 30 #

Therefore, -6a = 30

4 0
3 years ago
Jing is helping the kindergarten teacher put together bags of crayons. Each bag has 4 crayons, and 1/4 of the crayons in each ba
wariber [46]

Answer:

A)  \frac{3}{12}

Step-by-step explanation:

Given:

Jing is helping the kindergarten teacher put together bags of crayons.

Each bag has 4 crayons, and 1/4 of the crayons in each bag are green.

What fraction of the crayons in 3 bags are green?

<u>Solution:</u>

1 bag contains number of crayons = 4

1 bag contains number of green crayons = \frac{1}{4} \ of\ 4 = \frac{1}{4}\times4=1

Total number of bags = 3

Total number of crayons in 3 bags = 4 \times 3 = 12

1 bag contains number of green crayons = 1

Total number of green crayons in 3 bags = 1  \times 3 = 3

Fraction of the green crayons out of total = 3 out of 12 = \frac{3}{12}

Therefore, fraction of the crayons in 3 bags are green are  \frac{3}{12}

7 0
4 years ago
A department store will place a sale item in a special display for a one-day sale. Previous experience suggests that 43 percent
Svetradugi [14.3K]

Answer:

672.7436 units of the sale item should the store stock in order to have at most a 1 percent chance of running short of the item on the day of the sale

Step-by-step explanation:

No. of customers pass the display on the day of sale = 1462

Proportion of people will purchase if pass such a special display = 0.43

Mean = E(X)=np

E(X)=1462 \times 0.43

E(X)=628.66

Standard deviation = \sqrt{npq}

Standard deviation =\sqrt{1462 \times 0.43 \times (1-0.43)}=18.92

Now we are supposed to find how many units of the sale item should the store stock in order to have at most a 1 percent chance of running short of the item on the day of the sale

P(X<x)=0.01

Using z table

P(\frac{x-\mu}{\sigma})= 2.33 \\\frac{x-628.66}{18.92}=2.33\\x=(2.33 \times 18.92)+628.66\\x=672.7436

Hence 672.7436 units of the sale item should the store stock in order to have at most a 1 percent chance of running short of the item on the day of the sale

5 0
3 years ago
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