Solve the equation x^4-64=0

Mathematics

2 answers:

ki77a [65]3 years ago

6 0

Answer:

Step-by-step explanation:

x^4=64

x^2= +- 8

x = +-sqrt2, x= +- i sqrt2

mina [271]3 years ago

4 0

Answer:

Step-by-step explanation:

x^4-64=0

factor

(x^2+8)(x^2-8)=0

zero property

x^2+8=0, x^2-8=0

x^2=0-8-8,

x^2=-8,

x^2=0+8=8,

x^2=8,

----------------

sqrt(8) & sqrt(-8),

gives you 2*sqrt(2) and -2*sqrt(2),

also, the square root of a negative number contains the imaginary number, i. Because sqrt(-1)=i, don't forget this formula.

So sqrt(-8)=2i*sqrt(2) and -2i*sqrt(2).

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We need to subtract the mean from each value and square it.
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Now we add up the new values ( also consider their frequency) and find their mean.
Add the values
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Divide by total numburs to find the mean
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The standar deviation is the square root of the mean so is
Square root of 61.43223333=7.837871735
Round to the nearest tenth
Standard Deviation is 7.8

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