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GuDViN [60]
3 years ago
6

Serena wants to create snack bags for a trip she is going on. She has 6 granola bars and 10 pieces of dried fruit. If the snack

bags should be identified without any food leftover, what is the greatest number of snack bags Serena can make?
Mathematics
1 answer:
Rainbow [258]3 years ago
5 0

Answer:

2

Step-by-step explanation:

Given the question :

Serena wants to create snack bags for a trip she is going on. She has 6 granola bars and 10 pieces of dried fruit. If the snack bags should be identified without any food leftover, what is the greatest number of snack bags Serena can make?

Number of granolas = 6

Number of dried fruits = 10

Since the snackbag is to be designed in such a way that there should be no food leftover, the greatest number of snack bags Serena can make could be obtained by getting the highest common factor of (6 and 10)

____6____10

2___3____5

Here, the highest common factor of 6 and 10 is 2

Hence, the greatest number of snack bags she can make is 2.

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Erin wants to carpet the floor of her closet. A floor plan of the closet is 4ft x 10ft x 3ft x 6ft. How much carpet does Erin ne
yKpoI14uk [10]
1720 ft^2 you just need to times all the numbers together.
7 0
3 years ago
A football is kicked up into the air. Its height, H, above the ground, in meters, at t seconds can be modelled by () = 24 − 4.9^
MrRa [10]

Correct question is;

A football is kicked up into the air. Its height, H, above the ground, in meters, at t seconds can be modelled by () = 24 − 4.9²

(a) Determine the expression for the instantaneous rate of change in height at time t.

(b) Determine ' (2) What does ' (2) represent?

Answer:

A) '() = 24 − 9.8

B) '(2) = 4.4 m/s

It means that at a distance of 2 m above the ground, the speed of the ball is 4.4 m/s

Step-by-step explanation:

We are given the function to represent the height as;

() = 24 − 4.9²

A) expression for the instantaneous rate of change in height at time t will be gotten by differentiation of the height function. Thus;

'() = 24 − 9.8

B) '(2) = 24 - 9.8(2)

'(2) = 4.4 m/s

This means that at a distance of 2 m above the ground, the speed of the ball is 4.4 m/s

7 0
3 years ago
What is the area of the obtuse triangle below?
Lilit [14]
<span>All triangles use the same formula for area: 1/2 * B * H</span>
6 0
4 years ago
A ball is thrown upward with an initial velocity of 16 ft/sec from a height of 32 ft above the ground. The height, in feet, of t
GaryK [48]

Answer:  2 seconds.

Step-by-step explanation:

Given : A ball is thrown upward with an initial velocity of 16 ft/sec from a height of 32 ft above the ground.

The height, in feet, of the ball t sec after it is thrown can be represented by

s=-16t^2+16t+32.

When ball reaches the ground , s= 0.

\Rightarrow -16t^2+16t+32=0

Divide both sides by 16 , we get

-t^2+t+2=0\\\\\Rightarrow\ t^2-t-2=0\\\\\Rightarrow\ t^2-2t+t-2=0\\\\\Rightarrow\ (t-2)(t+1)=0 \\\\\Rightarrow\ t=2,-1

But time cannot be negative , so t= 2.

Hence , it will take 2 seconds for the ball to reach the ground.

8 0
3 years ago
If discount rate is 12%, the present value of Rs X recieved at the end of each year for the next five years is equal to
myrzilka [38]

Answer:

Present Value = X [\frac{1}{(1 + 0.12)^{1} }  + \frac{1}{(1 + 0.12)^{2} }  + \frac{1}{(1 + 0.12)^{3} }  + \frac{1}{(1 + 0.12)^{4} }  + \frac{1}{(1 + 0.12)^{5} } ]

Step-by-step explanation:

To find - If discount rate is 12%, the present value of Rs X received at the end of each year for the next five years is equal to .... ?

Solution -

We know that, formula for finding the Present vale is given by

Present value = Future value / (1 + r)ⁿ

where r is the rate of interest

and n is Number of periods

Now,

Here in the question, we have

r = 12% = 12/100 = 0.12

n = 5

Also, Given that, we have received Rs X at the end of each year

So,

Present Value = \frac{X}{(1 + 0.12)^{1} }  + \frac{X}{(1 + 0.12)^{2} }  + \frac{X}{(1 + 0.12)^{3} }  + \frac{X}{(1 + 0.12)^{4} }  + \frac{X}{(1 + 0.12)^{5} }

                        = X [\frac{1}{(1 + 0.12)^{1} }  + \frac{1}{(1 + 0.12)^{2} }  + \frac{1}{(1 + 0.12)^{3} }  + \frac{1}{(1 + 0.12)^{4} }  + \frac{1}{(1 + 0.12)^{5} } ]

⇒Present Value = X [\frac{1}{(1 + 0.12)^{1} }  + \frac{1}{(1 + 0.12)^{2} }  + \frac{1}{(1 + 0.12)^{3} }  + \frac{1}{(1 + 0.12)^{4} }  + \frac{1}{(1 + 0.12)^{5} } ]

7 0
3 years ago
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