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zhannawk [14.2K]
3 years ago
10

2H2S + 3O2 mc008-1.jpg 2SO2 + 2H2O Which option gives the correct mole ratios?

Chemistry
1 answer:
lianna [129]3 years ago
3 0
<span>Consider the balanced equation below.

2H2S + 3O2 ---> 2SO2 + 2H2O

Which option gives the correct mole ratios?
H2S:SO2 = 2:2 and O2:H2O = 3:2
H2S:SO2 = 2:3 and O2:H2O = 3:2
H2S:SO2 = 4:4 and O2:H2O = 5:4
H2S:SO2 = 4:6 and O2:H2O = 4:4</span>



is the aswer   H2S:SO2=2:2 and O2:H2O=3:2

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Given that a chlorine-oxygen bond has an enthalpy of 243 kJ/mol , an oxygen-oxygen bond has an enthalpy of 498 kJ/mol , and the
Alecsey [184]

Explanation:

The chemical equation is as follows.

      \frac{1}{2}Cl_{2}(g) + \frac{1}{2}O_{2}(g) \rightarrow ClO(g)

And, the given enthalpy is as follows.

    \frac{1}{2}Cl_{2}(g) + O_{2}(g) \rightarrow ClO_{2}(g);  \Delta H = 102.5 kJ

    Cl-Cl = 243 kJ/mol,      O=O = 498 kJ/mol

Since, the bond enthalpy of Cl-Cl is not given so at first, we will calculate the value of Cl-Cl as follows.

   \Delta H = \sum \text{bond broken in reactants} - \sum \text{bond broken in products}

    102.5 = [(\frac{1}{2})x + 498] - [(2)(243)]

    102.5 = (\frac{1}{2})x + 498 - 486

     102.5 - 12 = \frac{x}{2}

           x = 181 kJ

Now, total bond enthalpy of per mole of ClO is calculated as follows.

       \Delta H = \sum E(\text{bond broken in reactants}) - \sum (\text{bond broken in products})

              x = [(\frac{1}{2})181 + (\frac{1}{2})498] - 243

                 = 339.5 - 243

                 = 96.5 kJ

Thus, we can conclude that the value for the enthalpy of formation per mole of ClO(g) is 96.5 kJ.

8 0
3 years ago
What makes sherbet fizzy​
Tasya [4]

Answer:

The chemical reaction between the citric acid and sodium bicarbonate

Explanation:

8 0
3 years ago
Compare the mass of the Mg ribbon with the mass of the magnesium oxide. Notice that the the mass of the magnesium oxide is great
Artist 52 [7]

Answer:

Magnesium oxide is a binary compound of magnesium and oxygen while magnesium ribbon consists only of magnesium atoms.

Explanation:

The burning of magnesium in oxygen is a chemical change. It produces magnesium oxide having greater mass than magnesium ribbon. The greater mass results from the fact that the chemical reaction has added another element to the sample- oxygen. The mass of magnesium ribbon is the mass of magnesium atoms alone but in magnesium oxide, we consider the masses of magnesium and oxygen atoms making magnesium oxide heavier than magnesium ribbon.

4 0
3 years ago
Is 2H2 + O2=2H2O a balanced equation
Mnenie [13.5K]

Explanation:

Yes, the equation is balanced. There are the same number of Hydrogen (H) and Oxygen (O) atoms on both sides of the equation.

7 0
3 years ago
6NaBr+1AlO3=3Na2O+2AlBr3 How many grams of NaBr would be needed in order to make 23.5 grams of AlBr3
Evgesh-ka [11]

Answer:

23.5 grams of AlBr3 will be produced by 27.20 grams of NaBr

Explanation:

The balanced equation here is

6NaBr + 1AlO3 = 3Na2O + 2AlBr3

6 moles of NaBr are required to produce 2 moles of AlBr3

Mass of one mole of NaBr = 102.894 g/mol

Mass of one mole of AlBr3 = 266.69 g/mol

Mass of 6 moles of NaBr = 6*102.894 g/mol

Mass of two moles of AlBr3 = 2*266.69 g/mol

6*102.894 g  NaBr produces 2*266.69 g of AlBr3

23.5 grams of AlBr3 will be produced by (6*102.894)/(2*266.69 )*23.5 = 27.20 grams of NaBr

6 0
3 years ago
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