What is the air temperature 8,850 m in the air?
1 answer:
You might be interested in
The specific gravity of a sample is the ratio of the density of the sample with respect to one standard sample. The standard sample used in specific gravity calculation is water whose density is 1 g/mL. The solution having specific gravity 1.30 is the density of the sample that is 1.30 g/mL. Thus the weight of the 30 mL sample is (30×1.30) = 39 g.
Now the mass of the 10 mL of water is 10 g as density of water is 10 g/mL. Thus after addition the total mass of the solution is (39 + 10) = 49g and the volume is (30 + 10) = 40 mL. Thus the density of the mixture will be g/mL. Thus the specific gravity of the mixed sample will be 1.225 g/mL.
Explanation:
The given data is as follows.
= 1.5 atm,
= 20 L,
= (28 + 273) K = 301 K
= 5 atm,
= ?,
= (50 + 273) K = 323 K
Formula to calculate the volume will be as follows.
=
Putting the given values into the above formula as follows.
=
=
= 0.64 L
Thus, we can conclude that the change in volume of the balloon will be 0.64 L.