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Bond [772]
3 years ago
10

Solve the formula for the indicated variable h= k/j, for k

Mathematics
2 answers:
Flauer [41]3 years ago
7 0

The answer here is

K=he

MrMuchimi3 years ago
4 0

k=hj

do u mean to make subject of k

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In a series of operations without grouping symbo,multiplication and division are performed first TRUE or FALSE?​
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Is the line through points P(–3, –2) and Q(2, 3) perpendicular to the line through points R(10, –1) and S(15, –6)? Explain.
Alexus [3.1K]

Answer:

B. Yes. Their slopes have product -1.

Step-by-step explanation:

Given:

Line passing through P(-3, -2) and Q(2, 3)

Line passing through R(10, -1) and S(15, -6)

Required:

To determine if both lines are perpendicular.

SOLUTION:

Two lines are considered perpendicular if the product of their slopes equal -1.

To determine if both lines given in the question are perpendicular, first, calculate their slope using: m = \frac{y_2 - y_1}{x_2 - x_1}

Slope of line passing through P(-3, -2) and Q(2, 3):

Let,

P(-3, -2) = (x_1, y_1)

Q(2, 3) = (x_2, y_2)

m = \frac{3 -(-2)}{2 -(-3)}

m = \frac{5}{5} = 1

Slope of line passing through R(10, -1) and S(15, -6):

Let,

R(10, -1) = (x_1, y_1)

S(15, -6) = (x_2, y_2)

m = \frac{-6 -(-1)}{15 - 10}

m = \frac{-5}{5} = -1

The product of their slopes = 1 × -1 = -1

<u><em>Therefore, the lines are perpendicular.</em></u>

The answer is: <em><u>B. "Yes. Their slopes have product -1."</u></em>

5 0
3 years ago
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