D. 1/4
Explanation:
a perfect square is written in the form
(1)
In our problem, we have this perfect square:
(2)
with C being unknown. However, by comparing (1) and (2), we know that
So, we find
and therefore, the missing term must be
so the complete square is
Answer:
This is NOT a function. Because if you used the vertical line test it would hit that line 2 times.
Step-by-step explanation:
Given:
The line passing through (-2,5) and (2,p) has a gradient of 
.
To find:
The value of p.
Solution:
If a line passes through two points, then the slope of the line is:
The line passing through (-2,5) and (2,p). So, the slope of the line is:
It is given that the gradient or slope of the line is .
On cross multiplication, we get
Divide both sides by 2.
Therefore, the value of p is 3.
Well if you have 60 and she has 120 i will set it out as a sequence week by week
60,67,74,81,88,95,102,109,116,123,130,137,144,151,158,165,172,179,186,193,200,207,214,221,228,235,242,249,256,263,270
120,125,130,135,140,145,150,155,160,165,170,175,180,185,190,195,200,205,210,215,220,225,230,235,240, 245,250,255,260,265,270
it would take 31 weeks and the total is 270
Answer:
The correct option is;
Increasing one fifth unit/sec
Step-by-step explanation:
The equation that gives the curve of the particle of the particle is y = 5·x² - 1
The rate of decrease of the y value dy/dt = 2 units per second
We have;
dy/dx = dy/dt × dt/dx
dy/dx = 10·x
dy/dt = 2 units/sec
dt/dx = (dy/dx)/(dy/dt)
dx/dt = dy/dt/(dy/dx) = 2 unit/sec/(10·x)
When x = 1
dx/dt = 2/(10·x) = 2 unit/sec/(10 × 1) = 1/5 unit/sec
dx/dt = 1/5 unit/sec
Therefore, x is increasing one fifth unit/sec.
