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2 years ago

Show twelve in four different ways

1 answer:

5 0

12 can be shown in four different ways by performing subtraction, addition, multiplication, and/or division:

14 - 2
6 + 6
3 x 4
60 / 5

All of these expressions result in 12.

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Julissa is running a 10-kilometer race at a constant pace. After running for 18 minutes, she completes 2 kilometers. After runni

vodomira [7]

First, we need her speed as it will serve as the slope of the equation.
Distance = 2 km
time = 18 min
Speed = 1/9 km/min
k = (1/9)t
Where k is the distance in km and t is the time in minutes.

6 0

3 years ago

How many equivalence relations are there on the set 1, 2, 3]?

Alex787 [66]

Answer:

We need to find how many number of equivalence relations are on the set {1,2,3}

A relation is an equivalence relation if it is reflexive, transitive and symmetric.

equivalence relation R on {1,2,3}

1.For reflexive, it must contain (1,1),(2,2),(3,3)

2.For transitive, it must satisfy: if (x,y)∈R then (y,x)∈R

3. For symmetric, it must satisfy: if (x,y)∈R,(y,z)∈R then (x,z)∈R

Since (1,1),(2,2),(3,3) must be there is R, (1,2),(2,1),(2,3),(3,2),(1,3),(3,1). By symmetry,

we just need to count the number of ways in which we can use the pairs (1,2),(2,3),(1,3) to construct equivalence relations.

This is because if (1,2) is in the relation then (2,1) must be there in the relation.

the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

we can have three possible equivalence relations:

{(1,1),(2,2),(3,3),(1,2),(2,1)}

{(1,1),(2,2),(3,3),(1,3),(3,1)}

{(1,1),(2,2),(3,3),(2,3),(3,2)}

6 0

3 years ago

Please help me out thx

Shalnov [3]

Answer would be the second one

A U B = B

7 0

2 years ago

In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.

Tema [17]

Answer:

$Area \approx 1149\ cm^2$

Step-by-step explanation:

<u>Given that:</u>

ΔUVW,

Side w = 44 cm, (It is the side opposite to $\angle W$ )

Side u = 83 cm (It is the side opposite to $\angle U$ )

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

$A = \dfrac{1}{2}\times a\times b\times sinC$

Where a and b are the two sides and

$\angle C$ is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

$A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A \approx 1149\ cm^2$

So, the <em>area </em>of given triangle to the nearest square centimetre is:

$Area \approx 1149\ cm^2$

8 0

3 years ago

G es to prove that if a, b, and c are integers, where a ≠ 0 and c ≠ 0, such that ac | bc, then a |

Alex Ar [27]

$ac\mid bc$ means there exists an integer $n$ such that $ac=bcn$ . We can divide both sides by $c$ because $c\neq0$ . This implies $a=bn$ for some integer, which is identically $a\mid b$ .

3 0

3 years ago