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2 years ago

Mrs. Mack teaches three art classes, and there are 30 students in each dass. She has a supply

Mathematics

1 answer:

laila [671]2 years ago

6 0

Answer: 3/5

Step-by-step explanation:

1. Multiply 30 by 3 (90)

2. 90 becomes the numerator and 150 becomes the denominator

3. Divide the numerator (90) and the denominator (150) by the greatest common factor (30), to simplify the fraction

4. You should come to the answer 3/5

Hope this helps.

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For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 28 N acts on

SVEN [57.7K]

Answer:

Step-by-step explanation:

F=ma

28=7m

m=28/7=4

F=4a

when a=3 m/s²

F=4×3=12 N

8 0

2 years ago

Simplify ( √ 5)(^3 √ 5) the answer will be a wholenumber and a fraction

arlik [135]

Answer:

$\sqrt{5}\cdot\sqrt[3]{5} =\sqrt[6]{5^3} \cdot\sqrt[6]{5^2} =\sqrt[6]{5^5} =5^{(5/6)}$

Step-by-step explanation:

The rules of exponents apply, even when they are fractional exponents:

$a^b\cdot a^c=a^{b+c}\\\\\sqrt[b]{x^a}=x^{(a/b)}$

6 0

3 years ago

1.) Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth .x squared minus 21 x equals n

Andrew [12]

Part 1
We are given $x^2-21x=-4x$ . This can be rewritten as $x^2-18x=0$ .
Therefore, a=1, b=-18, c=0.
Using the quadratic formula
$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(1\right)\left(0\right)}}{2\left(1\right)}$
$x=\frac{18\pm 18}{2}$

The values of x are
$x_1=\frac{18-18}{2}=0$
$x_2=\frac{18+18}{2}=18$

Part 2
Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a quadratic function.

Part 3.
The first equation is $y=x^2+2$ .
The second equation is $y=3x+20$ .

We have
$x^2+2=3x+20$
$x^2-3x-18=0$
Factoring, we have
$\left(x-6\right)\left(x+3\right)=0$
Equating both factors to zero.
$x_1-6=0\rightarrow x_1=6$
$x_2+3=0\rightarrow x_2=-3$

When the value of x is 6, the value of y is
$y=3\left(6\right)+20=38$

When the value of x is -3, the value of y is
$y=3\left(-3\right)+20=11$

Therefore, the solutions are (6,38) or (-3,11)

7 0

2 years ago

Which expression is a monomial?

creativ13 [48]

I need options but this is an example of a monomial:

(2x^2)

5 0

3 years ago

In the figure below ABCD is a rectangle and DA and CB are radii of circles tangent externally, AB = 4 cm. Provide the answer in

ad-work [718]

Answer:

a. Radius of DA - 2 cm.

b. Area of rectangle ABCD -

c. Area of shaded - 8-4π

d. Perimeter of shaded region - also 8-4π

<em><u>Hope this helps! </u></em>

3 0

2 years ago