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qwelly [4]
3 years ago
14

Find the probability of selecting two number cards when two cards are

Mathematics
2 answers:
QveST [7]3 years ago
8 0

We know that there are 36 number cards and 16 face cards in standard deck of 52 cards. Now choose two cards without replacement from 52 cards.

The number of ways of choosing any 2 cards without replacement from 52 cards is

C(2,52)=\frac{52!}{50!2!}  .

The number of ways of choosing 2 number cards without replacement from 36 cards is

C(2,36)=\frac{36!}{34!2!}  .

The required probability is

\frac{\frac{36!}{34!2!}}{\frac{52!}{50!2!}  } =\frac{35*36}{51*52} =\frac{105}{221}  

Correct choice is (A)

olga2289 [7]3 years ago
6 0

We know that there are 36 number cards and 16 face cards in standard deck of 52 cards. Now choose two cards without replacement from 52 cards.

The number of ways of choosing any 2 cards without replacement from 52 cards is

C(2,52)=\frac{52!}{50!2!}.

The number of ways of choosing 2 number cards without replacement from 36 cards is

C(2,36)=\frac{36!}{34!2!}.

The required probability is

\frac{\frac{36!}{34!2!}}{\frac{52!}{50!2!}  } =\frac{35*36}{51*52} =\frac{105}{221}

Correct choice is (A).

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RSB [31]

Answer:

5:10

6 (-2,0)

7 (-5,6)

8 (5,3)

9 No, ab=8 CD=6

Step-by-step explanation:

4 0
2 years ago
SLOPE IN MATH PLEASE HELP I’LL MARK BRAINLIEST + A LOT OF POINTS
Fed [463]

Answer:

-7/9

Step-by-step explanation:

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7 0
3 years ago
For the data in the table, write an equation for the direct variation.
melisa1 [442]

The equation of direct variation is,

\begin{gathered} y=kx \\ k=\frac{y}{x} \end{gathered}

Substitute the values of <em>y</em> and <em>x</em>.

\begin{gathered} k=\frac{5.4}{4} \\ k=1.35 \end{gathered}

So, the obtained equation will be <em>y</em>=1.35(x).

Let's check with the values of <em>x</em>.

1) If <em>x</em>=4

\begin{gathered} y=1.35x \\ y=1.35(4) \\ y=5.4 \end{gathered}

2) If <em>x</em>=2

\begin{gathered} y=1.35x \\ y=1.35(2) \\ y=2.7 \end{gathered}

3) If <em>x</em>=-2

4 0
1 year ago
If 2 is added to both the numerator and denominator of a fraction its value becomes half. If two is subtracted from both the num
Hitman42 [59]

Answer:

The original fraction is \frac{6}{14}.

Step-by-step explanation:

Solution,

Let the fraction be'\frac{x}{y}'.

Where 'x' is the numerator and 'y' is the denominator.

Now according to question, if 2 is added to both the numerator and denominator the value of the fraction becomes 1/2.

So, framing the above sentence in equation form, we get;

\frac{x+2}{y+2}=\frac{1}{2}

On using cross multiplication method, we get;

2(x+2)=y+2\\\\2x+4=y+2\\\\2x+4-2=y\\\\\therefore\ y=2x+2\ \ \ \ equation\ 1

Now according to question, if 2 is Subtracted to both the numerator and denominator the value of the fraction becomes 1/3.

So, framing the above sentence in equation form, we get;

\frac{x-2}{y-2}=\frac{1}{3}

On using cross multiplication method, we get;

3(x-2)=y-2\\\\3x-6=y-2\\\\3x-y=-2+6\\\\3x-y=4 \ \ \ \ equation\ 2

Now Substituting the equation 1 in equation 1 we get;

3x-y=4\\\\3x-(2x+2)=4\\\\3x-2x-2=4\\\\3x-2x=4+2\\\\x=6

Now Substituting the value of x in equation 1 we get;

y=2x+2\\\\y=2\times6+2 = 14

Hence The original fraction is \frac{6}{14}.

4 0
3 years ago
Plz help with these first one gets brainliest
vlabodo [156]

Answer:

A=(1,6) B=(1,6)

Step-by-step explanation:

Its the absolotle value between them.

4 0
2 years ago
Read 2 more answers
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