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Ahat [919]
3 years ago
5

1) Mister Smith wants to put a small fence around his garden. A store sells three feet sections of fence at cost of $5.49 per se

ction. In the number of feet, what is the longest length of fence can he purchase if he wants to spend less than 145 dollars on the fence? Assume Mister Smith cannot purchase a fraction of a section of fencing and must purchase only whole sections. Show work and explain your reasoning.
2) A lifeguard at a swimming pool gives one-hour swim lessons to children in the morning before the pool is open to the public. She earns four dollars per class and fifty cents per swimmer. The minimum wage in her state is $7.25. She hopes to earn more than that amount of money during each class. Write an inequality that models the situation and find the minimum number of students she must teach in each class so that her earnings for that hour exceeds the minimum wage in her state.

3) Every year a classroom of students holds a car wash to raise money to help fund a good cause in their community. This year the class wants to purchase Electric Blankets for their local Senior Citizens Center. Each blanket costs 52 dollars. Their teacher says every year the class raises between 2,000 and 2,500 dollars. Using that estimate, what inequality below BEST represents how many blankets (B) the class can expect to buy for the Center?
A) B>2000
B) 2000
C) B<2500
D) 38<=B<=48

4) Jimmy does yard work around his neighborhood. In a given week he works at least two days, but no more than five. And on the days he does work, he earns at least three dollars per day, but no more than seventeen dollars per day. Write an inequality that models how much money (M) Jimmy makes per week.
A) 5<=M<=22
B) 3<=M<=17
C) 6<=M<=85
D) 2<=M<=5

5) A school wants to put on a dance recital. Middle School dancers have short programs that run four minutes long. High School performers will dance longer with longer programs seven minutes in length. The entire program cannot have more than ten dances and the entire recital must be over in less than 90 minutes. What pair of inequalities BEST represents the number of short Middle School dances (M) and the number of longer High School dances (H) that can be performed given these limitations?

A) M+H>=10,4M+7H<90

B) M+H<=10,4M+7H<90

C) 4M+7H<=10,4M+7H<90

D) M+H<=10,M+H<90

when answer can you please put the number of the question so i know which answer belongs to which question Thanks for your help :)
Mathematics
1 answer:
Gelneren [198K]3 years ago
5 0
1. Mister Smith spends $145 total. The number of sections is$ 145/$ 5.49 = 26.41 ~ 27 sectionsThe length of the fence is27 (3) = 81 feet
2. Let x be the number of students in each class. The inequality is0.5x + 4 > 7.25
3. D) 38<=B<=48 
4. C) 6<=M<=85 
5. B) M+H<=10,4M+7H<90 
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Khan sold his cycle at loss of 8%.had He sold it for 240 more he would have gained 12%
denpristay [2]

Khan sold his cycle at loss of 8%.had He sold it for 240 more he would have gained 12%. Then cost price is $ 1200 and selling price is $ 1104

<h3><u>Solution:</u></h3>

Assume the cost price be "a"

So the selling price of cycle = a - 8% of a

\text { selling price }=a-\frac{8 a}{100}=\frac{23 a}{25}

Now according to given, had He sold it for 240 more he would have gained 12%

Selling price + 240 = cost price + 12% profit

\frac{23a}{25} + 240 = a + \frac{12a}{100}

\frac{23a + 6000}{25} = \frac{100a + 12a}{100}\\\\92a + 24000 = 112a\\\\20a = 24000\\\\a = 1200

So the cost price is $ 1200

Now the selling price = \frac{23a}{25} = \frac{23 \times 1200}{25} = 1104

So the selling price is $ 1104

7 0
4 years ago
-7.2x+3.5=-8.7x-10 help plz
m_a_m_a [10]
-7.2x + 8.7x = -3.5 - 10
1.5x = -13.5
x = -13.5/1.5
x = -9
5 0
3 years ago
Find the area please
Natasha2012 [34]

Answer:

7.07

Step-by-step explanation:

3 0
3 years ago
What is the radius of a circle with an area of 400(pi) cm^2?
ivanzaharov [21]

Answer:  r≈11.28

Step-by-step explanation:

                         

5 0
4 years ago
In a survey, the planning value for the population proportion is p* = 0.35. How large a sample should be taken to provide a 95%
lions [1.4K]

Answer:

n=\frac{0.35(1-0.35)}{(\frac{0.05}{1.96})^2}=349.59  

And rounded up we have that n=350  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p represent the real population proportion of interest

\aht p represent the estimated proportion for the sample

n is the sample size required (variable of interest)

z represent the critical value for the margin of error

Solution to the problem

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:  

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)

And replacing into equation (b) the values from part a we got:  

n=\frac{0.35(1-0.35)}{(\frac{0.05}{1.96})^2}=349.59  

And rounded up we have that n=350  

6 0
3 years ago
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