You can use the trigonometric identity

.

The requirement that

eliminates -1/6 from being another solution.
The given data is
t, h: 0 2 4 6 8 10
r(t), L/h: 8.6 7.9 6.8 6.4 5.7 5.3
The lower and upper estimates for the total amount that leaked may be computed as the Left and Right Riemann sums.
The shape of the graph of r versus will determine which of the two sums yields an upper or lower sum.
The plot of the graph is shown below.
The Left Riemann sum is
Sl = 2*(8.6+7.9+6.8+6.4+5.7) = 70.8 L
The Right Riemann sum is
Sr = 2*(7.9+6.8+6.4+5.7+5.3) = 64.2 L
Answer:
The lower estimate for oil leakage is 64.2 L
The upper estimate for oil leakage is 70.8 L
Answer:
x=-17/5
Step-by-step explanation:
1. Simplify -6x-3x+4+4x−6x−3x+4+4x to -5x+4−5x+4.
21=−5x+4
2. Subtract 44 from both sides.
21−4=−5x
3. Simplify 21-4 to 17.
17=-5x
4. Divided both sides by -5.
-17/5=x
5. Switch sides.
x=-17/5
Hope this helps.
3x^2 - 8x + 5
3x^2 - 3x - 5x + 5
3x(x - 1) - 5(x - 1)
(x - 1)(3x - 5)
The answer is: (x - 1)(3x - 5).
Answer:
1: 3/4 = 6/8 = 9/12
2: 2/3 = 4/6 = 6/9
3: 8/9 = 16/18 = 24/27
Step-by-step explanation: