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jasenka [17]
3 years ago
13

Daniel invests $2,037 in a retirement account with a fixed annual interest rate of 6% compounded 6 times per year. What will the

account balance be after 16 years?
Mathematics
1 answer:
notka56 [123]3 years ago
4 0

Answer:

\$5294.72

Step-by-step explanation:

GIVEN: Daniel invests \$2,037 in a retirement account with a fixed annual interest rate of 6\% compounded 6 times per year.

TO FIND: What will the account balance be after 16 years

SOLUTION:

Amount invested by Daniel =\$2037

Annual interest rate =6\%      

Total amount generated by compound interest is  =P(1+\frac{r}{n})^n^t

Here Principle amount P=\$2037

rate of interest r=6\%

number of times compounding done in a year n=6

total duration of time nt=16\text{ years}

putting values we get

=2037(1+\frac{6}{6\times100})^1^6

=2037(\frac{101}{100})^1^6

=\$5294.72

Hence the total balance after 16\text{ years} will be \$5294.72

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777dan777 [17]

Answer:

  • ratio: 2/3
  • sum: 73 8/9

Step-by-step explanation:

The general term of a geometric sequence is ...

  an = a1·r^(n-1)

You have the 2nd and 4th terms, so ...

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We can find r from the ratio ...

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Then r is ...

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The first term is ...

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  a1 = (3/2)·18 = 27

__

The sum of the first 6 terms is ...

  Sn = a1·(r^n -1)/(r -1)

  S6 = 27·((2/3)^6 -1)/(2/3 -1)

  S6 = 27·(64/729-1)/(2/3-1) = (27)(665)/243 = 73 8/9

The sum of the first 6 terms is 73 8/9.

_____

<em>Check on the sum</em>

The first 6 terms are ...

  27, 18, 12, 8, 5 1/3, 3 5/9

Their sum is 73 8/9, as above.

8 0
3 years ago
-3(x+0.6)=6(x+2.4)<br> Could you possibly show the work also?
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Step-by-step explanation:

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