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Akimi4 [234]
3 years ago
7

If, for a sample in which the subjects are randomly chosen, the mean income is $45,000, the sample size is 1600, the standard de

viation is $4,000, and the standard error of the mean is $10, what, approximately, is the 95% confidence interval for the population mean?
Mathematics
1 answer:
jeka57 [31]3 years ago
6 0

Just add 45'000, 4,000, 10,divided by 95% = your answer.

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Ava deposited $14 in a savings account that earns 2.7% simple interest. What would the graph look like?
katen-ka-za [31]

Deposited amount = $14.

Rate of interest =  2.7%

In decimals 2.7 could be written by dividing 2.7 by 100, we get

0.027.

Interest earned each year = 2.7% of $14 = 0.027*14 = $0.378.

We can make a table to balance by after each year.

First year balance: First year interest + Deposited amount = 0.378 +14 = $14.378.

Second year balance: Second year interest + Deposited amount = 2*0.378 +14 = 0.756+ 14 = $14.756.

Third year balance: Third year interest + Deposited amount = 3*0.378 +14 = 1.134+ 14 = $15.134.

We get four coordinates to graph A(0,14), B(1, 14.378) , C(2, 14.756) and D(3, 15.134).

Plotting those coordinates of the points A, B, C and D on the graph.



8 0
4 years ago
I need help I can't figure out how to do this. I have to find the value of v. 4/5(v−7)=2
Nina [5.8K]
9.5 because 9.5-7 is 2.5. 2.5 times 4/5 is 10/5 which is equivalent to 2. 4/5(2.5-7)=2
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3 years ago
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6 0
3 years ago
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Evaluate the function when x=−2, 0, and 5. g(x)=3x−2
kipiarov [429]
I hope this helps....

x=-2
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3 years ago
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Bingel [31]

= 3/8-14

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I hope that's help !

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