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3 years ago

WILL GIVE BRAINLIEST

Mathematics

1 answer:

Wittaler [7]3 years ago

3 0

In the equation 40+70+?=360, they are trying to find the last angle.

First they would add 40 and 70, which is 110.

So 110+?=360

360-110=?

360-110=250

Well this is wrong, because every angle in a triangle adds up to 180 degrees.

If you are adding up the angles in a quadrilateral, only then it adds up to 360 degrees.

So they did everything right, but they didn't use the right "total degrees"

This is what it was supposed to look like.

40+70+?=180

110+?=180

180-110=?

180-110=70

?=70

♡ Hope this helped! ♡

♡ Also thank you so much for 31 points. ♡

✿ Brainiest is appreciated! ✿

❀ 0ranges ❀

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A government report gives a 99% confidence interval for the proportion of welfare recipients who have been receiving welfare ben

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Answer:

The estimation for the proportion for this case is $\hat p = 0.21$

And we know that the 99% confidence interval is given by:

$0.21 \pm 0.045$

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

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Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

The estimation for the proportion for this case is $\hat p = 0.21$

And we know that the 99% confidence interval is given by:

$0.21 \pm 0.045$

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

If we decrease the confidence level this margin of error can't be higher than 0.045 so then the correct answer for this case would be:

d. 21% ± 4.8%

Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

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Add the tops. Hope this helps :)

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3 years ago

Read 2 more answers

A 2 cm x 2 cm x 2 cm cube holds 468 grains of rice. How many grains of rice would fit in a box with

Amiraneli [1.4K]

Let the Volume of the first cube be V1

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Let the Volume of the second cube be V2

V2 = 6 * 2 * 12

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Now, cube1 with volume of 8 cm*3 holds 468 grains of rice.

Thus, 1 cm*3 volume can hold 58.5 grains of rice ( 468 / 8 = 58.5)

Cube2 has volume of 144 cm*3.

Hence, it can hold 8424 grains of rice ( 144 * 58.5 = 8424)

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