The population of the town in 1960 is 48.80 thousands
<h3>How to determine the population in 1950?</h3>
The equation of the model is given as:
f(t) = 42e^(0.015t)
1960 is 10 years after 1950.
This means that:
t = 10
Substitute t = 10 in f(t) = 42e^(0.015t)
f(10) = 42e^(0.015 * 10)
Evaluate
f(10) = 48.80
Hence, the population of the town in 1960 is 48.80 thousands
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The cost for carpeting 20 square yards is $230.
Further explanation:
First of all, we will calculate the cost for one square yard then will find the final answer.
So,
Given
Total area = 28 square yards
Cost of carpeting 28 square yards = $322
Cost of carpeting one square yard = 322/28 = $11.5 per square yard
Now to find the cost of carpeting 20 square yards
Cost of 20 square yards = 20*11.5
= $230
The cost for carpeting 20 square yards is $230.
Keywords: Costing, Word Problems
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Answer:
c = 9/16
Step-by-step explanation:
<h3>step1</h3>
(a-b)²
a² - 2ab + b²
here a = x
b = ?
so
x² - (2)(x)(?) + ?²
Now we can see that -(2x)? = -3x/2
-2x? = -3x/2
cancel -x on both sides
2? = 3/2
? = 3/2 * (2)
? = 3/4
so b = 3/4
<h3>step2</h3>
(x² - 3x + 9/16) = (x-3/4)²
so from the expression we can see that C = 9/16
