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Julli [10]
3 years ago
8

What is the range of 90, 72, 150, 43, 84, 91, 65, 48? 105 106 107

Mathematics
1 answer:
Dovator [93]3 years ago
3 0

I believe the answer to be "107"

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Consider the graph and equation, y = 3x, that represent Alonso’s walking speed. What relationship is represented by this equatio
natita [175]

Answer:

The equation, y=3 x,

Step-by-step explanation:

y=Distance traveled

x =Total time

Also, in terms of straight line

Slope =3= uniform Velocity

Point (3,9) and (5,15) represents Distance traveled in 3 (unit of time) =9 unit, and 15 unit=Distance traveled in 5 (Unit of time).

→Alonso is moving with uniform speed=3 (unit of time), as velocity remains constant in the entire process.

6 0
4 years ago
What is the value of the expression below.4/5+3/5+3.5×5
Solnce55 [7]

Answer:

18.9

Step-by-step explanation:

4/5  +  3/5  +  3.5  * 5

Well using PEMDAS you would need to do 3.5 x 5 which is 17.5

After that you would to 4/5  + 3/5 which is 7/5 also as 1  2/5

Then you would do 7/5  +  17.5 = 18.9

I might be wrong but that is what I got and I hope it helps you :)

6 0
3 years ago
Select the graph that would represent the best presentation of the solution set.<br> \absP &gt; 3
m_a_m_a [10]

Answer:

Step-by-step explanation:

there's no graph selection attached. Can you upload it and then I can help?

4 0
2 years ago
Please help! posted picture of question
Dvinal [7]
Since the graph of the given functions is a straight line, the graph belongs to a linear function, as all linear functions have their graphs as a straight line. For a non-linear function the graph is not a straight line. 

For a relation (non-function), the line passes through same value of x for more than one points. 

Hence the correct answer is "Linear Function"
8 0
3 years ago
Graph the first six terms of a sequence where a1 = 2 and r = 4.
zavuch27 [327]
We are given with
a1 = 2
r = 4

These are components of a geometric series. The first term is 2 and the common ratio is 4. To get the first six terms, we use the formula:
an = a1 r^(n-1)
a1 = 2 (4)^(1-1) = 2
a2 = 2 (4)^(2-1) = 8
a3 = 2 (4)^(3-1) = 32
a4 = 2 (4)^(4-1) = 128
a5 = 2 (4)^(5-1) = 512
a6 = 2 (4)^(6-1) = 2048
8 0
3 years ago
Read 2 more answers
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