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BabaBlast [244]
2 years ago
13

Calculate a four-day moving average for the price of the stock for the end of day 7. day 1 - 62.00; day 2 - 56.00; day 3 - 50.00

; day 4 - 60.00; day 5 - 59.00; day 6 - 55.00; day 7 - 59.00; day 8 - 63.00 review later 59.00 58.25 56.25 57.00
Mathematics
1 answer:
Aneli [31]2 years ago
8 0

At day 7, the four-day moving average for the price of the stock would be $58.25.

<h3>What is the four-day moving average at day 7?</h3>

This can be found as:

= (Day 7 price + Day 6 + Day 5 + Day 4) / Number of days

Solving gives:

= (59 + 55 + 59 + 60) / 4

= 233 / 4

= $58.25

Find out more on moving averages at brainly.com/question/15188858.

#SPJ1

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Cloud [144]

Answer:

Total amount = R5112

Step-by-step explanation:

Let the cooks be C.

Let the waiters be W.

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Number of cooks, C = 2

Number of waiters, W = 3

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b. To find the amount earned by each waiter;

W = 30 * R28 = R840

c. To find the total amount earned by the employees;

Total amount = 2C + 3W

Total amount = 2(1296) + 3(840)

Total amount = 2592 + 2520

Total amount = R5112

4 0
2 years ago
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dybincka [34]

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(2x^9y^n) (4x²y^10)-8x^11 y^20                        i say the answer 1 or 10

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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30

(2x^9y^n) (4x²y^10)-8x^11 y^20

1

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(2x^9y^n) (4x²y^10)-8x^11 y^20

1

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(2x^9y^n) (4x²y^10)-8x^11 y^20

1

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(2x^9y^n) (4x²y^10)-8x^11 y^20

1

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(2x^9y^n) (4x²y^10)-8x^11 y^20

1

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30

(2x^9y^n) (4x²y^10)-8x^11 y^20

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30

(2x^9y^n) (4x²y^10)-8x^11 y^20

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30

(2x^9y^n) (4x²y^10)-8x^11 y^20

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2

10

30

(2x^9y^n) (4x²y^10)-8x^11 y^20

1

2

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30

(2x^9y^n) (4x²y^10)-8x^11 y^20

1

2

10

30

(2x^9y^n) (4x²y^10)-8x^11 y^20

1

2

10

30

(2x^9y^n) (4x²y^10)-8x^11 y^20

1

2

10

30

(2x^9y^n) (4x²y^10)-8x^11 y^20

1

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10

30

(2x^9y^n) (4x²y^10)-8x^11 y^20

1

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10

30

(2x^9y^n) (4x²y^10)-8x^11 y^20

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10

30

(2x^9y^n) (4x²y^10)-8x^11 y^20

1

2

10

30

4 0
1 year ago
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RSB [31]

Answer:

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7 0
2 years ago
I need help on this question
deff fn [24]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
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sammy [17]
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4 0
2 years ago
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