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3 years ago

5.Find the coordinates of the midpoint of the segment

Mathematics

2 answers:

Digiron [165]3 years ago

8 0

Answer:

Midpoint formula: (x1+x2/2, y1+y2/2)

Step-by-step explanation:

Take your x points and place them into the formula and then take your y points and do the same.

Gemiola [76]3 years ago

4 0

Answer:

(first)x+(second)x/2(fraction), (first)y+(second)y/2(fraction

Step-by-step explanation:

If you add the x values together and the y values together and divide them both by two you will get your x value for the midpoint and then your y value for the midpoint

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Step-by-step explanation:

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3 years ago

Given △DEF, which is not equal to cos(F)? sin(F). sin(D). tan(F). cos(D)

valentina_108 [34]

Answer: The correct option is tan(F).

Explanation:

In the given figure the triangle is a right angle triangle because $\angle E=90^{\circ}$ .

It is also given that $DE=EF=5$ and $DF=5\sqrt{2}$ .

Since it is an isosceles right angle triangle, therefore the value of perpendicular and base is same for both angles D and F, which is 5.

$\cos (F)=\frac{Base}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}$

The value of cos(F) is $\frac{1}{\sqrt{2}}$ .

$\sin (F)=\frac{Perpendicular}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}$

The value of sin(F) is $\frac{1}{\sqrt{2}}$ .

$\sin (D)=\frac{Perpendicular}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}$

The value of sin(D) is $\frac{1}{\sqrt{2}}$ .

$\tan (F)=\frac{Perpendicular}{Base}=\frac{5}{5} =1$

The value of tan(F) is 1. Which is not equal to $\frac{1}{\sqrt{2}}$ .

$\cos (D)=\frac{Base}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}$

The value of cos(D) is $\frac{1}{\sqrt{2}}$ .

Therefore, the value of tan(F) is not equal to the value of cos(F), so the correct option is third.

3 0

3 years ago

Read 2 more answers

Which of these is a ratio table?

Fittoniya [83]

Answer: last one

Step-by-step explanation:

It's the only one with a solid rate of change

5 0

3 years ago

(02.06 MC)

Paul [167]

The inequality |2x − 6| less than or equal to 10 can be expressed as two form like this to get two value of x
2x-6 ≤ 10
2x≤10+6
x≤8

-(2x-6) ≤ 10
2x-6 ≥ -10
2x≥-10+6
x≥-4

The graph of the inequality would be: 
x≤8 and x≥-4
or
-4≤x≤8

5 0

4 years ago