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Kisachek [45]
3 years ago
15

Wolfrich lived in Portugal and Brazil for a total period of 14 months in order to learn Portuguese. He learned an average of 130

new words per month when he lived in Portugal, and an average of 150 new words per month when he lived in Brazil. In total, he learned 1920 new words. How long did Wolfrich live in Portugal and how long did he live in Brazil?
Mathematics
1 answer:
Ghella [55]3 years ago
7 0
He lived 9 months in Portugal and 5 months in Brazil. This is because 130*9 + 150*5 = 1920.
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The owner of an auto repair shop studied the waiting times for customers who arrive at the shop for an oil change. The following
labwork [276]

Answer:

(d)0.6

Step-by-step explanation:

(a)Frequency Distribution

\left|\begin{array}{c|c}$Waiting Time(in Minutes)&$Frequency\\-----------&--\\0-4&4\\5-9&8\\10-14&5\\15-19&2\\20-24&1\\--&--\\Total&20\end{array}\right|

(b)The relative frequency distribution.

\left|\begin{array}{c|c}$Waiting Time(in Minutes)&$Relative Frequency\\-----------&--\\0-4&4/20=0.2\\5-9&8/20=0.4\\10-14&5/20=0.25\\15-19&2/20=0.1\\20-24&1/20=0.05\\--&--\\Total&1\end{array}\right|

(c)The cumulative frequency distribution.

\left|\begin{array}{c|c|c}$Waiting Time(in Minutes)&$Frequency&$Cumulative Frequency\\-----------&--&---\\0-4&4&4\\5-9&8&12\\10-14&5&17\\15-19&2&19\\20-24&1&20\\--&--&--\\Total&20\end{array}\right|

(d)The proportion of customers needing an oil change who wait 9 minutes or less.

Proportion of customers needing an oil change who wait 9 minutes or less.

=\dfrac{12}{20} \\\\=0.6

5 0
3 years ago
Mrs. Smith's class is working on a variety of science experiments. Each
SVETLANKA909090 [29]

Answer:

66

Step-by-step explanation:

If there are  <em>n</em>  students, then the number of pairs is \frac{n(n-1)}{2}.

With 12 students, \frac{12(12-1)}{2} = \frac{132}{2}=66 pairs can be formed.

The reason the formula works is this:  Each of the 12 students can be paired with 11 other students (no student is paired with him/her self).  But counting 12 x 11 = 132  counts each pair <u>twice</u>.  Example: student A can be paired with student B,..., student B can be paired with student A.  The pair was counted two times.

See the attached image that shows pairings of 5 students.  There are

5(5 - 1)/2 = 5(4)/2 = 10 pairs.

8 0
3 years ago
The object on the right is made from a square-based pyramid joined to a cuboid.
spayn [35]

Answer:

Density of steel = 80.73 gm/cm^3

Step-by-step explanation:

The figure is made up of cuboid and square pyramid.

Height of cuboid, h = 9 cm

Length of cuboid, l = 6 cm

Width of cuboid, w = 6 cm

Volume of cuboid is given by the formula:

V_{Cuboid} = l \times w \times h

V_{Cuboid} = 6 \times 6 \times 9\\\Rightarrow V_{Cuboid} = 324\ cm^3

Density of Wood , D_{Cuboid}= 0.68g/cm^3

We know that formula of Density is:

Density = \dfrac{Weight}{Volume}

D_{Cuboid} = \dfrac{W_{Cuboid}}{V_{Cuboid}}\\\Rightarrow W_{Cuboid} = V_{Cuboid} \times D_{Cuboid}

Putting the values:

W_{Cuboid} = 324 \times 0.68 = 220.32\ gm

Total weight = W_{Cuboid} + W_{Pyramid}

970 = 220.32 + W_{Pyramid}

W_{Pyramid} = 749.68 gm

Volume of pyramid is given as:

V_{Pyramid}= \dfrac{1}{3} \times \text{Area of Base} \times \text{Vertical Height}

Base is a square with side 6 cm

V_{Pyramid}= \dfrac{1}{3} \times 6 \times 6 \times (17 -9)\\V_{Pyramid}= 96\ cm^3

Density of Steel/Pyramid:

D_{Pyramid} = \dfrac{W_{Pyramid}}{V_{Pyramid}}\\\Rightarrow D_{Pyramid} = \dfrac{749.68}{96}\\\Rightarrow D_{Pyramid} = 80.73\ gm/cm^3

5 0
3 years ago
A student union cafeteria worker checked the weight of ten half-pound bags of whole bean coffee and recorded the following weigh
Likurg_2 [28]

Answer: σ = 0.0154

Step-by-step explanation:

1. Calculate the mean for the recorded data.

(0.48 + 0.51 + 0.47 + 0.49 + 0.49 + 0.50 + 0.52 + 0.48 + 0.49 + 0.51)/10 =

4.94 / 10 = 0.49

The mean is represented with the greek letter μ, so μ = 0.49

2. For each element in the serie, subtract the mean (0.49) and square the result

(0.48 - 0.49)^2 = (-0.01)^2 = 0.0001

(0.51 - 0.49)^2 = (0.02)^2 = 0.0004

(0.47 - 0.49)^2 = (-0.02)^2 = 0.0004

(0.49 - 0.49)^2 = 0

(0.49 - 0.49)^2 = 0

(0.50 - 0.49)^2 = (0.01)^2 = 0.0001

(0.52 - 0.49)^2 = (0.03)^2 = 0.0009

(0.48 - 0.49)^2 = (-0.01)^2 = 0.0001

(0.49 - 0.49)^2 = 0

(0.51 - 0.49)^2 = (0.02)^2 = 0.0004

So we get these results: 0.0001, 0.0004, 0.0004, 0, 0, 0.0001, 0.0009, 0.0001, 0, 0.0004

3. Now, we calculate the mean of these squared differences

(0.0001 + 0.0004 + 0.0004 + 0 + 0 + 0.0001 + 0.0009 + 0.0001 + 0 + 0.0004) / 10 =

(0.0024) / 10 = 0.00024

4. Now to get the standard deviation, we need to get the root of this last value (0.00024).

√(0.00024) = 0.0154

5. So that will be our standard deviation value:

σ = 0.0154

DONE!

7 0
3 years ago
4x-y=3 is it linear or no
valentina_108 [34]

Answer:NO dodo its wrong you cant d o 1 side to toehr u gotta do left to right then side to side the denominatior!:)

Step-by-step explanation:

EASY

6 0
3 years ago
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