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mixer [17]
3 years ago
13

If you combined these two polygons what new polygon could you create

Mathematics
2 answers:
Archy [21]3 years ago
5 0
A square because if you put one polygon on top it makes a square
Serjik [45]3 years ago
3 0
You would create a square
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Can you guys help me with my homework?
tatiyna

Answer:

3π=3×3.14 =9.42

7π=7×3.14=21.98

Step-by-step explanation:

so the distance around window , in feet be

3π=3×3.14=9.42

7π=7×3.14=21.98

8 0
3 years ago
Explain Conversions. Giving out easy questions, basically free points
Paul [167]

Answer:

the process of changing or causing something to change from one form to another.

similar to transformation

3 0
3 years ago
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If g(x) = 4x^2 - 16 were shifted 7 units to the right and 3 down, what would the
Kitty [74]

Answer:

The new equation is h(x)=4(x-7)^2-19

Step-by-step explanation:

Given : Function g(x) = 4x^2 - 16 were shifted 7 units to the right and 3 down.

To find : What would the  new equation be?​

Solution :

Shifting to the right with 'a' unit is

f(x)→f(x-a)

So, shifting g(x) 7 units to the right is

h(x) = 4(x-7)^2-16

Shifting to the down with 'b' unit is

f(x)→f(x)-b

So, shifting g(x) 3 units down is

h(x)=(4(x-7)^2-16)-3

h(x)=4(x-7)^2-19

The new equation is h(x)=4(x-7)^2-19

8 0
2 years ago
The area of a square mural pointed on the side of a building is 110 square feet. What is the best estimate of the side length of
natka813 [3]

Answer:

C

Step-by-step explanation:

Area of a square equals to the square of its side, therefor the side of a given area for a square is the square root of the area.

A = a^{2}\\a = \sqrt{A}\\a = \sqrt{110} = 10.48 ft

8 0
2 years ago
An arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up
Papessa [141]

Answer:

s(t)=-9.8t^2+49t+58.8

Step-by-step explanation:

We have been given that an arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up be the positive direction. Because gravity is the force pulling the arrow down, the initial acceleration of the arrow is −9.8 meters per second squared.

We know that equation of an object's height t seconds after the launch is in form s(t)=-gt^2+v_0t+h_0, where

g = Force of gravity,

v_0 = Initial velocity,

h_0 = Initial height.

For our given scenario g=-9.8, v_0=49 and h_0=58.8. Upon substituting these values in object's height function, we will get:

s(t)=-9.8t^2+49t+58.8

Therefore, the function for the height of the arrow would be s(t)=-9.8t^2+49t+58.8.

6 0
3 years ago
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