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3 years ago

A swimmer is racing to the other side of the

Mathematics

1 answer:

kiruha [24]3 years ago

4 0

Either B or C. They look exactly the same but I can’t tell because the photo is blurry

y intercept is 75 and x intercept is 75/2.5=30

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In a softeball league, 87 players play on seven different teams.Each team has at least 12 players which inequality gives the lar

Vedmedyk [2.9K]

Answer: The answer is 12.4285714

Step-by-step explanation: your welcome

6 0

3 years ago

From the mid-1960s to the early 1990s, there was a slow but steady decline in SAT scores. For example, take the Verbal SAT. The

daser333 [38]

Answer:

a) 7.68%

b) 3.38%

Step-by-step explanation:

(a) Estimate the percentage of students scoring over 700 in 1967.

The probability that a student scored over 700 in 1967 equals the area under the Normal curve with mean 543 and standard deviation 110 to the right of 700.

In Excel this value is found with the formula

=1-NORMDIST(700,543,110,1)

and in OpenOffice Calc

=1-NORMDIST(700;543;110;1)

(NORMDIST(700;543;110;1) gives the area to the left of 700, so 1-NORMDIST(700;543;110;1) gives the area to the right of 700)

and equals 0.07675

So, the percentage of students scoring over 700 in 1967 was 7.68%

(b) Estimate the percentage of students scoring over 700 in 1994.

The probability that a student scored over 700 in 1994 equals the area under the Normal curve with mean 499 and standard deviation 110 to the right of 700.

In Excel this value is found with the formula

=1-NORMDIST(700,499,110,1)

and in OpenOffice Calc

=1-NORMDIST(700;499;110;1)

and equals 0.03383

So, the percentage of students scoring over 700 in 1994 was 3.38%

5 0

4 years ago

The 150 residents of the town of wonderland were asked their age and whether they preferred vanilla, chocolate, or swirled froze

asambeis [7]

Residents who are under 25 years and those above are mutually exclusive. Let V = number of persons who take Vanilla under 25yrs and V' be the number of residents who are at least 25yrs who take Vanilla. Okay, so P(V) = 40/150 and P(V') = 15/150 P(V or V') = 40/150 + 15/150 = 0.366

8 0

3 years ago

I need some help with this question!!! 25 points!!

Aleksandr [31]

Answer:

D. 68 Degrees

Step-by-step explanation:

We have the hypotenuse and the adjacent, so we use cos

Cos-1 of Adjacent / Hypotenuse = 67.9756871

7 0

2 years ago

Find $ \left(\frac{5}{12}\right)^{4}\left(\frac{12}{15}\right)^{3} $.

vitfil [10]

Question:- Find

$\left(\frac{5}{12}\right)^{4}\left(\frac{12}{15}\right)^{3}$

Answer:-

$\left(\frac{5}{12}\right)^{4}\left(\frac{12}{15}\right)^{3}$

Taking power inside the bracket

$\frac{5^{4} }{ {12}^{4} } \times \frac{ {12}^{3} }{ {15}^{3} }$

$\frac{ {5}^{4} }{ {12}^{4 - 3} } \times \frac{1}{ {(5 \times 3)}^{3} } \\ \frac{ {5}^{4} }{12} \times \frac{1}{ {5}^{ 3 } \times {3}^{3} } \\ \frac{ {5}^{4 - 3} }{12 \times {3}^{3} } \\ \frac{5}{4 \times 3 \times {3}^{3} } \\ \frac{5}{4 \times {3}^{4} } = \frac{5}{4\times81 } \\ Answer-> \frac{5}{324}$

$Power\:Form-> \frac{ 5 }{12 \times {3}^{3} }$

8 0

3 years ago