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wariber [46]
3 years ago
13

A swimmer is racing to the other side of the

Mathematics
1 answer:
kiruha [24]3 years ago
4 0
Either B or C. They look exactly the same but I can’t tell because the photo is blurry

y intercept is 75 and x intercept is 75/2.5=30
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A group of friends are hiking on trail Y when they reach an intersection with trial X. Trail X is perpendicular to train Y. If t
kati45 [8]
I believe the answer is C
3 0
3 years ago
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Need help fast don't understand both A and B show work please
Shkiper50 [21]
Problem A
Usually the number of bits in a byte is 8 or 16 or 32 and recently 64. You don't have to write a formula to restrict it to this number of bits. You are not asked to do so. The general formula is 2^n - 1 for the problem of Millie and her golden keys. Somehow the system can be made to choose the right number of bits. Apple IIe s for example, used 8 bits and there was a location that told the processor that fact.

2^n - 1 <<<<< Answer

Problem B
In this case n = 4
2^n - 1 = 2^4 - 1 = 16 - 1 = 15


Millie can collect 15 keys <<<<<< Answer
5 0
3 years ago
The antibiotic clarithromycin is eliminated from the body according to the formula A(t) = 500e−0.1386t, where A is the amount re
PolarNik [594]

Answer:

Time(t) = 11.61 hours (Rounded to two decimal place)

Step-by-step explanation:

Given: The antibiotic  clarithromycin is eliminated from the body according to the formula:

A(t) = 500e^{-0.1386t}                 ......[1]

where;

A - Amount remaining in the body(in milligram)

t - time in hours after the drug reaches peak concentration.

Given: Amount of drug in the body is reduced to 100 milligrams.

then,

Substitute the value of A = 100 milligrams in [1] we get;

100= 500e^{-0.1386t}

Divide both sides by 500 we get;

\frac{100}{500}=\frac{ 500e^{-0.1386t}}{500}

Simplify:

\frac{1}{5} = e^{-0.1386t}

Taking logarithm both sides with base e, then we have;

\log_e (\frac{1}{5})= \log_e (e^{-0.1386t})

\log_e (\frac{1}{5})=-0.1386t         [ Using \log_e e^a =a ]

or

\log_e (0.2)=-0.1386t

-1.6094379124341 = -0.1386t

 [using value of \log_e (0.2) = -1.6094379124341 ]

then;

t = \frac{-1.6094379124341}{-0.1386}

Simplify:

t ≈11.61 hours.

Therefore, the time 11.61 hours(Rounded two decimal place) will pass before the amount of drug in the body is reduced to 100 milligrams


6 0
3 years ago
PLEASE PLEASE PLEASE HELP ME YALL‼️‼️‼️‼️‼️
Inessa [10]

Answer:

Hi .. im happy to help

answer is 0.033

Step-by-step explanation:

P = C(4,4)÷C(10,4)

P = 1 ÷ 30

p =  \frac{1 }{30}

p = 0.033

3 0
2 years ago
What is the solution of the system of equations? {7/2x−1/2y=9/23x−y=5 Enter your answer in the boxes. ( _ , _ )
dimulka [17.4K]

Answer:

(1, -2)

Step-by-step explanation:

I hope that helps :/

5 0
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