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3 years ago

6*10^-2 is how many times as 2•10-8

Mathematics

1 answer:

andreev551 [17]3 years ago

8 0

Answer:

200

Step-by-step explanation:

6*10^-2=0.06

2*10-8=12

12 divided by 0.06 is 200

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Write the three numbers less then 40 that have 2 and 5 as factors

ozzi

No. which have factors 2 & 5 have 2 & 5 as their prime factor
therefore, No. are :
2*5 = 10
2*5*2 = 20
2*5*3 = 30

3 0

3 years ago

Write an equation in slope intercept form of the line with a slope of -3/4 and y intercept of -5

raketka [301]

Given,
slope(m)=-3/4
y intercept (c)=-5
Then,
equation in slope intercept form is
y=mx+c
or, y=(-3/4)×x+(-5)
or, y=-3/4×x-5

5 0

3 years ago

-8x-10y=24;6x+-10x-10y

stiks02 [169]

Do you have a typo? ; < this maybe

4 0

4 years ago

PLEASE HELP ASAP!!!!

lina2011 [118]

<h3>Answer:</h3>

System

p + m = 10
0.8m = 0.4·10

Solution

p = m = 5 — 5 lb peanuts and 5 lb mixture

<h3>Step-by-step explanation:</h3>

(a) Generally, the equations of interest are one that models the total amount of mixture, and one that models the amount of one of the constituents (or the ratio of constituents). Here, there are two constituents and we are given the desired ratio, so three different equations are possible describing the constituents of the mix.

For the total amount of mix:

... p + m = 10

For the quantity of peanuts in the mix:

... p + 0.2m = 0.6·10

For the quantity of almonds in the mix:

... 0.8m = 0.4·10

For the ratio of peanuts to almonds:

... (p +0.2m)/(0.8m) = 0.60/0.40

Any two (2) of these four (4) equations will serve as a system of equations that can be used to solve for the desired quantities. I like the third one because it is a "one-step" equation.

So, your system of equations could be ...

p + m = 10
0.8m = 0.4·10

___

(b) Dividing the second equation by 0.8 gives

... m = 5

Using the first equation to find p, we have ...

... p + 5 = 10

... p = 5

5 lb of peanuts and 5 lb of mixture are required.

8 0

4 years ago

QUESTION 2. the feasible region shows the number of chairs x and tables y that a furniture company can build each week.

GalinKa [24]

Answer:

Part a) The company can not build 12 chairs and 5 tables

Part b) The company can build 18 chairs and 3 tables

Part c) The company can build 12,13,14,15,16 or 17 chairs

Step-by-step explanation:

we know that

If a ordered pair is a solution, then the ordered pair must be belong to the feasible region of the graph

Part a) Can the company build 12 chairs and 5 tables?

In this problem we have the ordered pair A(12,5)

Plot and verify if the point belong to the feasible region of the graph

see the attached figure to better understand the problem

The point A is not on the feasible region

therefore

The company can not build 12 chairs and 5 tables

Part b) Can the company build 18 chairs and 3 tables?

In this problem we have the ordered pair B(18,3)

Plot and verify if the point belong to the feasible region of the graph

see the attached figure to better understand the problem

The point B is on the feasible region

therefore

The company can build 18 chairs and 3 tables

Part c) One week, the company decides to build 4 tables. how many chairs can the company build?

For y=4

Find the value of x in the graph

The solutions point for y=4 tables are

(12,4), (13,4),(14,4),(15,4),(16,4) and (17,4)

therefore

The company can build 12,13,14,15,16 or 17 chairs

3 0

3 years ago