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Tcecarenko [31]
3 years ago
12

The factored form of 25p29 10 – 169?

Mathematics
1 answer:
Yanka [14]3 years ago
8 0

Answer:

I'm guessing you are trying to say this is 25p29=10-169 If not let me know in comments and I'll change it! But here is the answer: 72750<em>p</em><em>-</em><em>1</em><em>6</em><em>9</em>

<em>Expla</em><em>ined</em><em>:</em>

25p*29=10 – 169

solve=

72750p-169

Hope this helps! If so please mark brainliest and rate/heart if it did!

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earnstyle [38]
D for the 1st
B. For the 2nd
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C. The 4th
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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
diamong [38]

Answer:

 A-2, B-DNE*, C-3, D-DNE, E-4, F-1

---------------------

The first attachment shows the solutions to A and C.

The second attachment shows the solutions to E and F.

There are no real number solutions to systems B and D.

_____

In general, you can solve the linear equation for y, then substitute that into the quadratic. You can subtract the x-term on the left and complete the square to find the solutions.

A.

 (3-x) +12 = x^2 +x

 15 = x^2 + 2x

 16 = x^2 +2x +1 = (x +1)^2 . . . . add the square of half the x-coefficient to complete the square; next take the square root

 ±4 -1 = x = {-5, 3) . . . . . identifies the second solution set for system A

__

B.

 (x -1) -15 = x^2 +4x

 -16 = x^2 +3x

 -13.75 = x^2 +3x +2.25 = (x +1.5)^2

roots are complex: -1.5 ±i√13.75

__

C.

 (1-2x) +5 = x^2 -3x

 6 = x^2 -x

 6.25 = x^2 -x + .25 = (x -.5)^2

 ±2.5 +.5 = x = {-2, 3} . . . . . identifies the third solution set for system C

__

remaining problems are done in a similar way.

_____

* DNE = does not exist. There is no matching solution set for the complex numbers that are the solutions to this.

---------------------

<em>Hope this helps!</em>

<em />

<u>Brainliest would be great!</u>

<u />

---------------------

<em><u>With all care,</u></em>

<em><u>07x12!</u></em>

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4 years ago
Find the equation of the line that is perpendicular to y =
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3 0
3 years ago
Read 2 more answers
Anyone wanna help?please
timama [110]

\large\underline{\underline{\red{\rm\blue{\longmapsto} Step-by-step\: Explanation:-}}}

Given to points to us are :-

  • ( 3 , -6 )
  • ( -1 , -8 )

( As these are plotted on graph with yellow dots .)

Now , we can use Distance Formula , which is :-

\boxed{\pink{\tt Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}}

Here ,

  • x1 = 3 .
  • x2 = -1.
  • y1 = (-6)
  • y2 = (-8).

<u>→ Substituting the respective values , </u>

⇒ Distance = √ [ { 3 - (-1)}² + { -6 -(-8)²} ] .

⇒ Distance = √ (3+1)² + (8-6)²

⇒ Distance = √ 4² + 2²

⇒ Distance = √ 16 + 4

⇒ Distance = √20 = √4 × √5

⇒ Distance = 4√5units .

<u>Hence the distance between two points is 4√5u.</u>

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4 years ago
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blondinia [14]
I believe y=-x+8 cause you would take the 2 then subtract it to the 16 for it to turn into 2y=-2x+16 then you take the 2y and divide
7 0
3 years ago
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