Do I need to include the $50 and the $25 she earned each week or just the $25 she earned each week. Please help, it’s due today

The scatter plot shows the number of DVDs Aaron sold in different months:

netineya [11]

We'll say that months = n.

Make a set of the DVD's sold:

${20, 50, 80, 110, 140...}$

In month 1, Aaron sold 20 DVDs. There is no data for month 0.

There is a constant increase of 30 DVDs every month. We can make an equation out of this to fit this data set:

$a = 30n - 10$

a represents the DVDs made.

We need to subtract 10 in this equation, as the starting point is 20, and the increase of 30 is different from the increase from n = 0 to n = 1.

We are looking for the amount of DVDs Aaron sold on the 13th month. Plug 13 into the equation:

$n = 13$
$30(13) - 10 = 390 - 10 = 380$

The predicted number of DVDs Aaron will sell on the 13th month is 380.

4 0

3 years ago

Read 2 more answers

I need help with this. Both Standard Deviation and the Mean. Both have answer choices of Decrease, Increase, or stay the same.

almond37 [142]

Answer:

The mean will stay the same.

The standard deviation will decrease.

Step-by-step explanation:

For the 5 cards, she has received, the mean will be:

μ=(∑x)/n

=125/5

=25

The mean is 25 and the standard deviation is 10.

σ=10

If a new card is received with $25, then the sum will be $150

So the new mean will be:

μ'=(∑x)/n

=150/6

=25

And the new standard deviation will be:

σ'= 9.12

We can clearly see that

μ= μ'

and

σ> σ'

So the mean will remain the same and standard deviation will decrease. .

4 0

3 years ago

For homework, Fred has to read 30 minutes daily. It takes him 2 minutes per page, and he spends 4 minutes viewing graphics in th

blondinia [14]

He must read 13 pages or more, because 13*2=26. 26+4=30. This is your answer, and I hope it helps.

8 0

4 years ago

If you made 20$ a week and your goal was 200$ how many days would it take to reach your goal?

wolverine [178]

It would take you 70 days.

4 0

3 years ago

Read 2 more answers

What are the conditions a sample needs to meet before you can assume it's binomial and that it approximates a normal distributio

Gemiola [76]

Answer:

1) $np\geq 5$

2) $nq = n(1-p)\geq 5$

Other conditions that are important are:

3) n is large

4) p is close to 1/2 or 0.5

Step-by-step explanation:

1) Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

2) Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n, p)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

In order to apply the normal apprximation we need to satisfy these two conditions:

1) $np\geq 5$

2) $nq = n(1-p)\geq 5$

Other conditions that are important are:

3) n is large

4) p is close to 1/2 or 0.5

8 0

4 years ago