All categories

2 years ago

Jose prefers to walk to work when the weather

Mathematics

1 answer:

stich3 [128]2 years ago

6 0

Answer:

independent: time (hours)

dependent: distance (miles)

Step-by-step explanation:

The independent variable would be time because it can be changed depending on his walking speed.

The dependent variable would be distance

You might be interested in

I need help with number 16

Sladkaya [172]

You are correct

for example f(1) = 3

and f(2) = f(2-1) - 2

= f(1) - 2

= 3 - 2 = 1

8 0

3 years ago

Read 2 more answers

Calculate the circumference and area of this circle. 4cm radius

Alja [10]

Answer:

the circumference is 25.133 and the area is 50.265

5 0

3 years ago

Read 2 more answers

When you divide a whole number by a fraction with a numerator of 1 how can you find the quotient

Mekhanik [1.2K]

You just take the denominator of the fraction used to divided the one and there is your answer. does this help

7 0

3 years ago

Owen has a 15 ft ladder, the instructions say that the base of the ladder should be 6 ft from the wall. How high up the wall wil

pogonyaev

Answer:

height = 13.75 feet

Step-by-step explanation:

use the Pythagorean theorem

hypotenuse^2 =base^2 + height^2

15^2 = 6^2+height^2

225 = 36 + height^2

189 = height^2

height = 13.75 feet

6 0

3 years ago

A positive integer from one to six is to be chosen by casting a die. Thus the elements c of the sample space C are 1, 2, 3, 4, 5

Alex_Xolod [135]

Answer with Step-by-step explanation:

We are given that six integers 1,2,3,4,5 and 6.

We are given that sample space

C={1,2,3,4,5,6}

Probability of each element= $\frac{1}{6}$

We have to find that $P(C_1),P(C_2),P(C_1\cap C_2) \;and\; P(C_1\cup C_2)$

Total number of elements=6

$C_1$ ={1,2,3,4}

Number of elements in $C_1$ =4

$P(E)=\frac{number\;of\;favorable \;cases}{Total;number \;of\;cases}$

Using the formula

$P(C_1)=\frac{4}{6}=\frac{2}{3}$

$C_2$ ={3,4,5,6}

Number of elements in $C_2$ =4

$P(C_2)=\frac{4}{6}=\frac{2}{3}$

$C_1\cap C_2$ ={3,4}

Number of elements in $(C_1\cap C_2)=2$

$P(C_1\cap C_2)=\frac{2}{6}=\frac{1}{3}$

$C_1\cup C_2=$ {1,2,3,4,5,6}

$P(C_1\cup C_2)=\frac{6}{6}=1$

4 0

3 years ago