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Lyrx [107]
2 years ago
5

Jose prefers to walk to work when the weather

Mathematics
1 answer:
stich3 [128]2 years ago
6 0

Answer:

independent: time (hours)

dependent: distance (miles)

Step-by-step explanation:

The independent variable would be time because it can be changed depending on his walking speed.

The dependent variable would be distance

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69 points!!!
Amiraneli [1.4K]

Answer:

C)  The solution for the given system of equations are A(0,-5) and B(-4,3)

Step-by-step explanation:

The given system of equation are : x^{2}  + y^{2}  = 25\\2x  + y  = -5

from equation 2, we get   y = -5 - 2x .

Put the above value of y in the equation (1).

We get: x^{2}  + y^{2}  = 25  \implies x^{2}  + (-5-2x)^{2}  = 25

By ALGEBRAIC IDENTITY:

(a+b)^{2}   = a^{2}  +  b^{2}  + 2ab\\ (-5-2x)^{2} = (-5)^{2}  +  (-2x)^{2}  + 2(-5)(-2x)

or, x^{2}  + (-5-2x)^{2}  = 25  \implies x^{2} + (25  +  4x^{2}  + 20x)  = 25

or, 5x^{2}  + 20x = 0  \implies x(5x + 20) = 0

⇒ x = 0 or,   x  = -20/5 = -4

So, the possible values for x are: x  = 0 or  x  = -4

If x  = 0, y = -5-2x = -5-2(0) = -5

and if x = -4, y = -5 -2(-4)   = -5 + 8  = 3

Hence, the solution for the given system of equations are A(0,-5) and B(-4,3)

8 0
3 years ago
Combine the like terms to create an equivalent expression: <br> 2s+(−4s)=?
Sergeeva-Olga [200]

Answer:

2s+\left(-4s\right)=-2s is the equivalent expression as 2s+\left(-4s\right) is equal to -2s.

Step-by-step explanation:

Considering the expression

2s+\left(-4s\right)

As we know that

  • Like terms are said to be the terms which hold the same variables raised to the same power.
  • For example, 3x and 2x are like terms as they contain the same variable x raised to the same power.

Lets solve the expression

2s+\left(-4s\right)

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

2s-4s

\mathrm{Add\:similar\:terms:}\:2s-4s=-2s

-2s

Therefore,

2s+\left(-4s\right)=-2s is the equivalent expression as 2s+\left(-4s\right) is equal to -2s.

Keywords: equivalent expression, like terms

Learn more about equivalent expression from brainly.com/question/8902137

#learnwithBrainly

4 0
3 years ago
Please help me solve this!!!!!!
BabaBlast [244]

Answer:

C. 9

Step-by-step explanation:

y = -4x^2 + 2kx

subtitute 3:

y = -4(9)^2 + 2k(9)

y = -4(81) + 18k

let y = 0

=> 0 = -324 + 18k

=> k = 324/18 = 9

this is my calculations hope it helps

4 0
2 years ago
Read 2 more answers
Find the circumference of a circle with diameter, d = 9.06m. Give your answer rounded to 2 DP
Olin [163]
C= 3.14d
C= 3.14 x 9.06
C= 28.45
5 0
2 years ago
Consider the two lines l1:x=−2t,y=1+2t,z=3tl1:x=−2t,y=1+2t,z=3t and l2:x=−8+4s,y=0+5s,z=5+1sl2:x=−8+4s,y=0+5s,z=5+1s find the po
seraphim [82]

At the point of intersection, the coordinates are the same:

... (x, y, z) = (-2t, 1+2t, 3t) = (-8+4s, 5s, 5+s)

We only need two of the coordinates to solve for the values of s and t. Using the x- and y-coordinates, we have

... 4s + 2t = 8 . . . . . . x2 - x1 = 0, in standard form

... 5s -2t = 1 . . . . . . . y2 - y1 = 0, in standard form

Adding these equations gives 9s=9, so s=1. Substituting into either equation gives t=2.

Using the expression for l1 with t=2, the point of intersection is

... (-2·2, 1+2·2, 3·2) = (-4, 5, 6).

_____

We could have stopped after finding the value of s, because that defines the point. By finding the value of t, we can check the solution to make sure that l1 and l2 both give the same point for the respective values of s and t. (They do.)

8 0
3 years ago
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