Question

Solve the quadratic equation numerically (using tables of x- and y- values).

Answer 1

Option C x = -6 or x = 1 IS CORRECT

Step-by-step explanation:

We need to solve the quadratic equation and find values of x.

The given quadratic equation is: $(x +2) (x + 3) = 12$

Solving:

$(x +2) (x + 3) = 12\\x(x+3)+2(x+3)=12\\x^2+3x+2x+6=12\\x^2+5x+6=12\\x^2+5x+6-12=0\\x^2+5x-6=0$

So, the quadratic equation is: $x^2+5x-6=0$

Now, factoring to find value of x:

$x^2+5x-6=0\\x^2+6x-x-6=0\\x(x+6)-1(x+6)=0\\(x-1)(x+6)=0\\x-1=0\,\,and\,\,x+6=0\\x=1\,\,and\,\,x=-6$

So, value of x are: x = 1 and x = -6

So, Option C x = -6 or x = 1 IS CORRECT.

Keywords: Quadratic Equation

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