The lengths of the two diagonals of a rhombus are 6 cm and 8 cm. Find the length of its perimeter (in
1 answer:
Answer:
<em>The perimeter of the rhombus is 20 cm</em>
Step-by-step explanation:
<u>Perimeter of a Rhombus</u>
Given the lengths of the two diagonals of a rhombus, let's call them a and b, the perimeter of the rhombus is given by:
The values of the diagonals provided by the question are a=6 cm, b=8 cm, thus the perimeter is:
The perimeter of the rhombus is 20 cm
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The picture in the attached figure
let
AB=x
we know that
perimeter of the figure=10*x
perimeter=42.5 cm
so
42.5=10*x
x=42.5/10
x=4.25 cm
area of the figure=area of rectangle +area of square
area of rectangle=4.25*(4.25*3)----> 54.1875 cm²
area of square=4.25²----> 18.0625 cm²
area of the figure=54.1875+18.0625-----> 72.25 cm²
the answer is
72.25 cm²
let
AB=x
we know that
perimeter of the figure=10*x
perimeter=42.5 cm
so
42.5=10*x
x=42.5/10
x=4.25 cm
area of the figure=area of rectangle +area of square
area of rectangle=4.25*(4.25*3)----> 54.1875 cm²
area of square=4.25²----> 18.0625 cm²
area of the figure=54.1875+18.0625-----> 72.25 cm²
the answer is
72.25 cm²