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2 years ago

The lengths of the two diagonals of a rhombus are 6 cm and 8 cm. Find the length of its perimeter (in

Mathematics

1 answer:

adelina 88 [10]2 years ago

3 0

Answer:

<em>The perimeter of the rhombus is 20 cm</em>

Step-by-step explanation:

<u>Perimeter of a Rhombus</u>

Given the lengths of the two diagonals of a rhombus, let's call them a and b, the perimeter of the rhombus is given by:

$P=2\sqrt{a^2+b^2}$

The values of the diagonals provided by the question are a=6 cm, b=8 cm, thus the perimeter is:

$P=2\sqrt{6^2+8^2}$

$P=2\sqrt{36+64}$

$P=2\sqrt{100}=2*10$

$P=20\ cm$

The perimeter of the rhombus is 20 cm

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2 years ago

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2 years ago

Read 2 more answers

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inessss [21]

Answer:

The answer is "94"

Step-by-step explanation:

Given data:

51,54,64,68,72,74,76,83,94,94,99

Find:

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2 years ago

Thallium-210 has a half-life of 1.32 minutes. Find an equation for the percent of Thallium-210 sample that remains after t minut

Lady bird [3.3K]

Answer:

p(t) = 100%·2^(-t/1.32)

Step-by-step explanation:

The equation for exponential decay is ...

(remaining amount) = (initial amount)·2^(-t/(half-life))

Here, we can represent the percentage remaining by p(t) and the initial amount by 100%. Then, for a half-life of 1.32 minutes, the amount remaining is ...

p(t) = 100%·2^(-t/1.32) . . . . . where t is in minutes

_____

Alternate functional forms are possible, such as ...

p(t) = 100%·e^(-0.525112t)

p(t) = 100%·0.591489^t

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2 years ago