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anygoal [31]
3 years ago
7

in the sequence of numbers a3=0 a4=6 a5=12 a6=18 a7=24 based on this information which equation can be used on the nth term in t

he sequence an
Mathematics
2 answers:
QveST [7]3 years ago
6 0
This is an=(n-3)*6
like a3= (3-3)*6
NeTakaya3 years ago
4 0

Answer:Tnth=6n-6

Step-by-step explanation:

a3=0,a4=6,a5=12,a6=18,a7=24

based on the information given it shows that it is arithmetic sequence since the common difference(d)=a6-a5=18-12=6

a2=a3-6=

a2=0-6=-6

a1=a2-6

a1=-6-6

a1=-12

Tnth=a+d(n-1)

Tnth=-12+6(n-1)

Tnth=-12+6n+6

Collect like terms

Tnth=-12+6+6n

Tnth=6n-6

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Write f(x)=8x^2-4x+11 in vertex form
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Answer:

f(x)=8(x-\frac{1}{4})^{2}+\frac{21}{2}

or

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Step-by-step explanation:

we have

f(x)=8x^{2}-4x+11

This is a vertical parabola open upward (because the leading coefficient is positive)

The vertex is a minimum

Convert to vertex form

Factor the leading coefficient

f(x)=8(x^{2}-\frac{1}{2}x)+11

Complete the square. Remember to balance the equation by adding the same constants to each side.

f(x)=8(x^{2}-\frac{1}{2}x+\frac{1}{16})+11-\frac{1}{2}

f(x)=8(x^{2}-\frac{1}{2}x+\frac{1}{16})+\frac{21}{2}

Rewrite as perfect squares

f(x)=8(x-\frac{1}{4})^{2}+\frac{21}{2} ----> equation in vertex form

or

f(x)=8(x-0.25)^{2}+10.5

The vertex is the point  (0.25,10.5)

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