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kipiarov [429]
3 years ago
11

I do not understand

Mathematics
2 answers:
gayaneshka [121]3 years ago
3 0
The answer is 4/7, because there are 4 hexagons and 7 total shapes
garri49 [273]3 years ago
3 0

Answer:

4/7

Step-by-step explanation:

there are 7 shapes in total, 4 of them are hexagons.

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The bike shop charges $10 for flat tire repair and $40 for a full tuneup. The total receipts for services was $3000. 10 tuneup’s
jonny [76]

Answer:

260 flat tyres were repaired.

<u>$400 </u>of sales in full tuneups

<u>$2600 </u>of sales in flat tyre repairs

Step-by-step explanation:

$40 x 10 = $400

$3000 - <u>$400</u> = $2600

<u>$2600</u> ÷ $10 = 260 flat tyres

7 0
4 years ago
3/8x - 1/4 =1/2<br><br> Please hurry
4vir4ik [10]

Answer:

x=2

Step-by-step explanation:

hope this helps :)

7 0
3 years ago
Please help : find x
neonofarm [45]

Answer:

Step-by-step explanation: um

3 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2
Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

but the integrand is even, so this is really just

\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

Substitute x = 1/2 arccot(u/2), which transforms the integral to

\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du

There are lots of ways to compute this. What I did was to consider the complex contour integral

\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}

and it follows that

\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}

7 0
2 years ago
Which linear equations does the graph show the
Digiron [165]

Answer:

Y=2×+13

Step-by-step explanation:

2×+3=0

2×=0-3

you use 3 to divide it self =×

×=3

7 0
3 years ago
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