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ASHA 777 [7]
3 years ago
11

Factorise the following questions

Mathematics
1 answer:
lesya692 [45]3 years ago
7 0

Answer:

ii)

\sqrt{2} x^{2}  + 3x +  \sqrt{2}   \\  =  \sqrt{2}x(x +  \sqrt{2} ) + x +  \sqrt{2} \\  = ( \sqrt{2} x + 1)(x +  \sqrt{2} )

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2//2/2/3/2/2//3/3/3//3/3/4/5/5​
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Explanation:  

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3 years ago
Which of the following terms describes the measure indicate...
o-na [289]
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The range shows the difference between the largest and the smallest number, and the black arrow below the graph in the picture shows is this distance between the largest and the smallest number. Hence, the answer is range.
6 0
3 years ago
Q 1 PLEASE HELP ME FIGURE THIS OUT 2
dimulka [17.4K]

Answer: \frac{\pi }{3}

<u>Step-by-step explanation:</u>

cot is \frac{cos}{sin} on the Unit Circle. When is cos = \frac{1}{2} and sin = \frac{\sqrt{3}} {2}?  In other words, where is the coordinate (\frac{1}{2},\frac{\sqrt{3}} {2}) on the Unit Circle?

It occurs at 60° = \frac{\pi }{3} radians

**************************************************************************************

Answer: cot θ

<u>Step-by-step explanation:</u>

  sec (90 - θ) * cos θ

= \frac{1}{cos (90 -\theta)} * cos θ

= \frac{cos\theta}{cos(90 - \theta)}

= \frac{cos\theta}{cos90*cos\theta+sin90*sin\theta}

= \frac{cos\theta}{0*cos\theta+1*sin\theta}

= \frac{cos\theta}{sin\theta}

= cot θ

**************************************************************************************

Answer: BC = √5, AC = 2√5

<u>Step-by-step explanation:</u>

\frac{\pi} {3} = 60°, which means ΔABC is a 30°-60°-90° triangle so we can use the side length formulas: x - x√3 - 2x.

∠C is the 60°. It matches to side AB so: AB = x√3 = √15   ⇒   x = √5

∠A is the 30°. It matches to side BC so: BC = x = √5

∠B is the 90°. It matches to side AC so: AC = 2x = 2(√5)  = 2√5

**************************************************************************************

Answer: k = 4, RS = 12, QS = 28

<u>Step-by-step explanation:</u>

\frac{QR}{MN} = \frac{RS}{NO}= \frac{QS}{MO}

\frac{24}{6} = \frac{RS}{3}= \frac{QS}{7}

proportionality constant k can be found with \frac{QR}{MN} = \frac{24}{6} = 4

\frac{QR}{MN} = \frac{RS}{NO}

→ 4 = \frac{RS}{3}

→ 4(3) = RS

→ 12 = RS

\frac{QR}{MN} = \frac{QS}{MO}

→ 4 = \frac{QS}{7}

→ 4(7) = QS

→ 28 = QS


3 0
3 years ago
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