Answer:
Present Time
Let X= Eric's age (4/5)X= Seth's age
Question: What are their ages now?________________________________________________________________________
Past (21 years ago)
X-21 =Eric's age (4/5)X-21=Seth's age
2*[4/5(X-21]=Eric's age
Therefore, X-21= 2*[4/5(X)-21]=Eric's age Substitution
_______________________________________________________________________
X-21= 8/5 X - 42 Solve for "X" by adding 42 to both sides.
X-21+42=(8/5) X
X+21 = (8/5)X Subtract "X" from both sides.
21=(3/5)X Multiply both sides of equation by reciprocal of (3/5), which is 5/3
21*(5/3)= X Finish the problem to find value of "X," which is Eric's age.
Then find 4/5 (X)= Seth's age
<u>Answer:</u> She misses 56 times at a soccer practice.
<u>Step-by-step explanation:</u>
Let the goals she misses be 'x'.
According to the question:
These two ratios follow direct relationship, so:
Hence, Vonna misses 56 times at a soccer practice.
Answer:
<em>5,9,13,17,21</em>
Step-by-step explanation:
We can the values in "n"
a(1)=4(1)+1
a(1)=5
a(2)=4(2)+1
a(2)=9
a(3)=4(3)+1
a(3)=13
a(4)=4(4)+1
a(4)=17
a(5)=4(5)+1
a(5)=21
As you can see, each value consecutively increases by 4, this is also known as the common difference (d).
31
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100 that's is what I got in the lowest form x
I believe it's the first one
