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chubhunter [2.5K]

4 years ago

8

Bus one had half of the grade eight students and 6 grade, seven students, bus two had 15 grade seven students and one-third of g

rade eight students, how many students are there in grade 8 ??
It's an algebra question

1 answer:

Rzqust [24]4 years ago

7 0

I'm not sure about that one

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Pls do it for me thank you so much

Bond [772]

Answer:

(a) Attached to this response.

(b)

<em>(i)</em> <em>0 cups = 0.275</em>

<em>(ii) 4 cups = 0.125</em>

<em>(iii) 8 cups = 0.025</em>

<em />

<em />

Step-by-step explanation:

(a) The frequency and relative frequency table has been attached to this response.

i. The first column, labelled x, is the number of cups of coffee consumed per day.

ii. The second column, labelled f, is the number of people that consumed x cups of coffee per day. It is found by counting the number of occurrences (i.e frequency) of the numbers of the first column, x, in the given data.

For example, 0 in first column appears 11 times in the given data. Also, 5 in the first column appears 4 times in the given data.

iii. The third column, labelled r, is the relative relative frequency of the number of cups of coffee. It is calculated by dividing the frequency of the cups of coffee by the total number of people that consumed it. As shown on the table, it is calculated by dividing the each of the values on the second column by the sum of the values on that same column (second column).

For example, the relative frequency of 2 cups of coffee is given by:

r = 7 ÷ 40 = 0.175

Also, the relative frequency of 4 cups of coffee is given by;

r = 5 ÷ 40 = 0.125

(b) The probability (Pₓ) that a randomly selected person consumed x cups of coffee is given by;

Pₓ = frequency of x ÷ total frequency

This is also the relative frequency of x

Therefore,

<em>(i) The probability (P₀) that a randomly selected person consumed 0 cups of coffee is given by;</em>

the relative frequency of 0<em> = 0.275</em>

<em></em>

<em>(ii) The probability (P₄) that a randomly selected person consumed 4 cups of coffee is given by;</em>

the relative frequency of 4<em> = 0.125</em>

<em>(iii) The probability (P₈) that a randomly selected person consumed 8 cups of coffee is given by;</em>

the relative frequency of 8<em> = 0.025</em>

<em></em>

<em></em>

<em></em>

5 0

3 years ago

I need help solving the problem

geniusboy [140]

29 - 29 x 15= 24.65
24.65 + 24.65 x .07= 26.3755 which rounds to 26.38
The answer is $26.38

3 0

3 years ago

PLEASE HELP!!! The side lengths of a square are each 5q. By adding 3 to the length and subtracting 3 from the width, a rectangle

Oksanka [162]

Answer:

Option C

Step-by-step explanation:

When you put the write the scenario in an equation, it'll look like

(5q+3)(5q-3) for the new width times the new length

Factor these, and you shall get 25q^2+15q-15q-9. Simplify that into

25q^2-9

8 0

3 years ago

The lee's spend $ 31 on movie tickets for 2 adults and 3 children. The Smith's spent $ 26 on movie tickets for 2 adults and 2 ch

Trava [24]

Answer:

Cost of adult ticket is $8 and Cost of children ticket is $5.

Step-by-step explanation:

Given:

Let the cost of each Adult ticket be 'x'.

Let the cost of each child ticket be 'y'.

Now Given:

The lee's spend $ 31 on movie tickets for 2 adults and 3 children.

Number of adult tickets = 2

Number of children ticket = 3

Total money spent = $31

So we can say that;

Total money spent is equal to sum Number of adult tickets multiplied by cost of each Adult ticket and sum Number of children tickets multiplied by cost of each child ticket.

framing in equation form we get;

$2x+3y=31 \ \ \ \ equation \ 1$

Also Given:

The Smith's spent $ 26 on movie tickets for 2 adults and 2 children

Number of adult tickets = 2

Number of children ticket = 2

Total money spent = $26

So we can say that;

Total money spent is equal to sum Number of adult tickets multiplied by cost of each Adult ticket and sum Number of children tickets multiplied by cost of each child ticket.

framing in equation form we get;

$2x+2y=26 \ \ \ \ equation \ 2$

Now Subtracting equation 2 from equation 1 we get;

$2x+3y-(2x+2y)=31-26\\\\2x+3y-2x-2y=5\\\\y=\$5$

Now substituting the value of y in equation 1 we get;

$2x+3y=31\\\\2x+3\times5 =31\\\\2x+15=31\\\\2x=31-15\\\\2x=16x\\\\\frac{2x}{2}\frac{16}{2}\\\\x=\$8$

Hence Cost of adult ticket is $8 and Cost of children ticket is $5.

6 0

3 years ago

Express -3/6 as a rational number with denominator 20

Usimov [2.4K]

Answer:

20 cause when According to Sciencealert, the longest math equation contains around 200 terabytes of text. Called the Boolean Pythagorean Triples problem, it was first proposed by California-based mathematician Ronald Graham, back in the 1980s.The Navier-Stokes equation, for me is the hardest of all. This is the full Navier-Stokes equation in conservative form. It looks pretty simple, but as one will dig in, they will notice why it is the hardest one.

4 0

3 years ago