False, both lines are oblique (diagonal) so they meet at some point on a graph. They can only have no solutions if the lines are parallel/have the same slope.
Answer:
9.50
Step-by-step explanation:
We are asked to factor out the expression:
4 x^3 - 10 x
So we extract a factor of "2" from the numerical factors "4" and "10", and also a factor of "x" from each term,leading to:
2 x ( 2 x^2 - 5)
Therefore, please select the first answer option they give you in the list.
Y1 is the simplest parabola. Its vertex is at (0,0) and it passes thru (2,4). This is enough info to conclude that y1 = x^2.
y4, the lower red graph, is a bit more of a challenge. We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).
Let's try this: assume that the general equation for a parabola is
y-k = a(x-h)^2, where (h,k) is the vertex. Subst. the known values,
-3-(-4) = a(2-0)^2. Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.
The equation of parabola y4 is y+4 = (1/4)x^2
Or you could elim. the fraction and write the eqn as 4y+16=x^2, or
4y = x^2-16, or y = (1/4)x - 4. Take your pick! Hope this helps you find "a" for the other parabolas.
