Which point represents the approximate location of 90 ? A) point A B) point B C) point C D) point D

Solve for x, y, and z

zloy xaker [14]

Answer:

The solution is x=1,y=2,z=3

Step-by-step explanation:

The given system of equations is ;\

2x−3y+4z=8...(1)

3x+4y−5z=−4...(2)

4x−5y+6z=12...(3)

Make x the subject in equation (1)

$x=\frac{8+3y-4z}{2}...(4)$

Put equation (4) into equation (2) and (3)

$3(\frac{8+3y-4z}{2})+4y-5z=-4$

Multiply through by;

$3(8+3y-4z)+8y-10z=-8$

Expand;

$24+9y-12z+8y-10z=-8$

Simplify;

$17y-22z=-32...(5)$

Equation (4) in (3)

$4(\frac{8+3y-4z}{2})-5y+6z=12$

$2(8+3y-4z)-5y+6z=12$

$16+6y-8z-5y+6z=12$

$y-2z=-4$

$y=2z-4...(6)$

Put equation (6) into equation (5)

$17(2z-4)-22z=-32$

$34z-68-22z=-32$

$34z-22z=-32+68$

$12z=36$

z=3

Put z=3 into equation (6)

y=2(3)-4=2

Put y=2 and z=3 into equation 4

$x=\frac{8+3(2)-4(3)}{2}=1$

The solution is x=1,y=2,z=3

3 0

3 years ago

A play was attended by 173 people. Adult tickets were $5 each and children paid $3 for each ticket the total revenue was $703. H

mr_godi [17]

The answer to this is 10545.

3 0

3 years ago

Read 2 more answers

A certain country's postal service currently uses 55-digit zip codes in most areas. how many zip codes are possible if there a

VashaNatasha [74]

There would be 100,000 if there are no restrictions on the digits and 90,000 if they cannot use 0 as the first digit.

If there are no restrictions, there are 10 possibilities for each digit:
10(10)(10)(10)(10) = 100,000

If the first digit cannot be 0, there are 9 possibilities for it and 10 possibilities for each of the other 4:
9(10)(10)(10)(10) = 90,000

8 0

3 years ago

These two trapezoids are similar What is the correct way to complete the similarity statement?

pentagon [3]

Option A:

$\mathrm{ABCD} \sim \mathrm{GFHE}$

Solution:

ABCD and EGFH are two trapezoids.

To determine the correct way to tell the two trapezoids are similar.

Option A: $\mathrm{ABCD} \sim \mathrm{GFHE}$

AB = GF (side)

BC = FH (side)

CD = HE (side)

DA = EG (side)

So, $\mathrm{ABCD} \sim \mathrm{GFHE}$ is the correct way to complete the statement.

Option B: $\mathrm{ABCD} \sim \mathrm{EGFH}$

In the given image length of AB ≠ EG.

So, $\mathrm{ABCD} \sim \mathrm{EGFH}$ is the not the correct way to complete the statement.

Option C: $\mathrm{ABCD} \sim \mathrm{FHEG}$

In the given image length of AB ≠ FH.

So, $\mathrm{ABCD} \sim \mathrm{FHEG}$ is the not the correct way to complete the statement.

Option D: $\mathrm{ABCD} \sim \mathrm{HEGF}$

In the given image length of AB ≠ HE.

So, $\mathrm{ABCD} \sim \mathrm{HEGF}$ is the not the correct way to complete the statement.

Hence, $\mathrm{ABCD} \sim \mathrm{GFHE}$ is the correct way to complete the statement.

3 0

3 years ago

The sum of the digits of a two-digit number is 5. If the number is multiplied by 3, the result is 42. Write and solve a system o

Elenna [48]

A two digit number has a tens digit and a ones digit.
Let's say x = tens digit and y = ones digit

"The sum of the digits is 5"
x + y = 5

The next phrase is "the number multiplied by 3 is 42" but we need to represent the number using the digits. So they need to be multiplied first by their place value and added together. [Example: 34 = 3(10) + 4(1)]

The number is: 10x + y
3(10x + y) = 42

The system of equations: (two equations for two unknowns)
x + y = 5
30x + 3y = 42

Then you can use substitution or elimination to combine and solve.
I'll use elimination, multiply the entire top equation by -3 and add the equations together. y will cancel out

-3x - 3y = -15
30x + 3y = 42
------------------
27x + 0 = 27
x = 1

then plug x = 1 into either equation to find y

1 + y = 5
y = 4

remember the x and y represent digits so the number xy is 14

6 0

3 years ago