Answer:
Teo is 11 years old and Richard is 26 years old.
Step-by-step explanation:
Let R be the age of Richard and T be the age of Teo.
<u><em>First set up the equations:</em></u>
The combined age of Teo and Richard is 37:
R+T=37
Richard is four years old than twice Teo's age:
R=2T+4
<u><em>Then, solve the equations:</em></u>
Substitute (2) to (1) and solve for T:
(2T+4)+T=37
3T=11
T=11
Solve for R using (2):
R=2(11)+4
R=22+4
R=26
The mean of the scores if 6 students in a competitive exam is 25 marks.
Given scores of 6 students are: 10,30,50,40,20 in a competitive exam.
We have to find out the mean of the mark of 6 students in a competitive exam.
Mean is the sum of all the values in a set of data, such as numbers, measurements, divided by the number of values. It is also known as average.
Mean=∑X/n
∑X=10+30+50+40+20
=150
N=6
Now to calculate the mean we have to divide 150 by number of students which is 6.
Mean=150/6
=25 marks.
Hence the mean of the scores of 6 students is 25 marks.
Learn more about mean at brainly.com/question/1136789
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Question is incomplete as it should include :
Marks of students =10,30,50,40,20.
Answer:
1.) He still owes $100 of debt
2.) 1 rose would be .75 cents and 1 carnation would be .90 cents
3.) C 8 and 3/8
Step by Step explanation
(/ means divided by in the first 2 equations but / in the last question is for the fractions.)
1.) _(1,500 / 3 =500. 1,500 - 500 =1,000 / 5 =200 x 3 =600. 700 - 600 =$100)
2.)_(1.50/2 =.75 cents. 2.70/3 =.90 cents.)
3.) i first added the fractions ( i equalized them) then i added the whole numbers (the u in the equation was to separate the whole num. and fraction )
Before i equalized it: (6u3/4 + 1u1/8 = 7u1/8 + 1/8 = 8u3/8)
After i equalized it: (6u6/8 + 1u1/8 = 7u1/8 + 1/8 = 8u3/8)
Answer:
87.92
Step-by-step explanation:
you have to multiply 3.14 by 2 which will give you 6.28, then you multiply 6.28 by 14 which gives you 87.92. hope this helps
