Question

Given that y=1/6^-x, write an equivalent equation in the form y=b^x, with 0

Answer 1

Negative exponents work like this:

$a^{-b}=\dfrac{1}{a^b}$

So, they work like positive exponents, but you have to invert the base.

If you invert 1/6 you get 6, so you have

$\left(\dfrac{1}{6}\right)^{-x}=6^x$