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3 years ago

6x+1 = -8x-13 pleasee

Mathematics

2 answers:

Yakvenalex [24]3 years ago

8 0

Answer:

$6x + 1 = - 8x - 13 \\ 6x + 8x = - 1 - 1 3 \\ 14x = - 14 \\ \frac{14x}{14} = \frac{ - 14}{14} \\ x = - 1$

hope this helps you.....

DiKsa [7]3 years ago

5 0

Answer: $x=-1$

Add 8x to both sides

$6x+1+8x=-8x-13+8x\\14x+1=-13$

Subtract 1 from both sides

$14x+1-1=−13-1\\14x=-14$

Divide both sides by 14

$14x/14=-14/14\\x=-1$

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A recently admitted class of graduate students at a large state university has a mean GRE verbal score of 650 with a standard de

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Answer:

The answer is below

Step-by-step explanation:

The z score is a score used to determine the number of standard deviations by which the raw score is above or below the mean, it is given by the equation:

$z=\frac{x-\mu}{\sigma} \\\\\mu=mean, \sigma=standard\ deviation,x=raw\ score\\\\for\ a\ sample\ n:\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }$

Given that μ = 650, σ = 50. To find the probability that 5 students who have a mean of 490, we use:

$z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{490-650}{50/\sqrt{5} } =-7.16$

From the normal distribution table, P(x < 490) = P(Z < -7.16) = 0.0001 = 0.01%

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4 0

3 years ago

1+1? Will give brainliest to first correct answer.

d1i1m1o1n [39]

Answer:

1+1= 2

have a nice day stay safe

3 0

2 years ago

Read 2 more answers

What is x, the distance between points A and A'? 2. 4 units 4. 8 units 13. 6 units 14. 4 units.

adelina 88 [10]

The distance between points A (3, -5) and A' (2, -3) is 2.4 units.

Given that,

The points A (3, -5) and A' (2, -3).

We have to determine,

The distance between point A and A'.

According to the question,

The distance between two points is determined by using the distance formula.

$\rm Distance \ formula = \sqrt{(x_2-x_2) ^2+ (y_2-y_2)^2$

Then,

The distance between points A (3, -5) and A' (2, -3) is,

$\rm Distance = \sqrt{(2-3) ^2+ ((-3)-(-5))^2}\\\\ Distance = \sqrt{(-1) ^2+ (2)^2}\\\\ Distance = \sqrt{1+4}\\\\Distance = \sqrt{5}\\\\Distance = 2.4 \ units$