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3 years ago

Find a line parallel to the graph of y=3x+6 that passes through the point (3,0) in standard form

Mathematics

1 answer:

Ivanshal [37]3 years ago

4 0

Answer:

The line parallel to this one and going through said point is y = 3x - 9

Step-by-step explanation:

In order to find this, we start by noting that the slope will be 3 because parallel lines have the same slope. Now we can use point-slope form to find the equation of the line.

y - y1 = m(x - x1)

y - 0 = 3(x - 3)

y = 3x - 9

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3 years ago

Four runners start at the same point; Lin, Elena, Diego, Andre. For each runner write a multiplication equation that describes t

Helen [10]

Answers:

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3 years ago

Find the value of x and y.

NeX [460]

Answer:

x = 4, y = 2

Step-by-step explanation:

Given quadrilateral is a parallelogram. Diagonals of a parallelogram bisects each other.

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4 years ago

Without a calculator, order the following expressions from least to greatest. 9, pie squared, 3 times pie??

Elden [556K]

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3 years ago

write an equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)

dimaraw [331]

The equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4) is $y - 3 = \frac{-7x}{2}+ \frac{21}{4}$

<h3>Solution:</h3>

Given that we have to write equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)

Let us first find the slope of given line AB

The slope "m" of the line is given as:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Here the given points are A(-2,2) and B(5,4)

$\text {Here } x_{1}=-2 ; y_{1}=2 ; x_{2}=5 ; y_{2}=4$

$m=\frac{4-2}{5-(-2)}=\frac{2}{7}$

Thus the slope of line with given points is $\frac{2}{7}$

We know that product of slopes of given line and slope of line perpendicular to given line is always -1

$\begin{array}{l}{\text {slope of given line } \times \text { slope of perpendicular bisector }=-1} \\\\ {\frac{2}{7} \times \text { slope of perpendicular bisector }=-1} \\ \\{\text {slope of perpendicular bisector }=\frac{-7}{2}}\end{array}$