Rob wants to work out how much energy his blue spotlights use. He turns the lights on at 9:00 am and leaves them on until 10:30
1 answer:
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The general formula for the frequency of the nth-harmonic of the column of air in the tube is given by
where f1 is the fundamental frequency.
In our problem, we have two harmonics, one of order n and the other one of order (n+1) (because it is the next higher harmonic), so their frequencies are
so their difference is
So, the difference between the frequencies of the two harmonics is just the fundamental frequency of the column of air in the tube, which is:
where f1 is the fundamental frequency.
In our problem, we have two harmonics, one of order n and the other one of order (n+1) (because it is the next higher harmonic), so their frequencies are
so their difference is
So, the difference between the frequencies of the two harmonics is just the fundamental frequency of the column of air in the tube, which is:
The initial speed of the boat is 
and its acceleration is
Since the boat is moving by uniform accelerated motion, the distance covered by the boat in a time t=10 s is given by:
So, the boat covers a distance of 350 m in 10 seconds.
and its acceleration is
Since the boat is moving by uniform accelerated motion, the distance covered by the boat in a time t=10 s is given by:
So, the boat covers a distance of 350 m in 10 seconds.
Explanation:
The given data is as follows.
mass, m = 75 g
Specific heat of water = 4.18
First, we will calculate the heat required for water is as follows.
q =
=
= 8464.5 J/mol
= 8.46 kJ ......... (1)
Also, it is given that = (20 + 273) K = 293 K and specific heat of ice is 2.108 kJ/kg K.
Now, we will calculate the heat of fusion as follows.
q =
=
= -46.32 kJ ......... (2)
Now, adding both equations (1) and (2) as follows.
8.46 kJ - 46.32 kJ
= -37.86 kJ
Therefore, we can conclude that energy in the form of heat (in kJ) required to change 75.0 g of liquid water at to ice at
is -37.86 kJ.