Answer:
CB = 4.45 x 10⁻⁹ F = 4.45 nF
Explanation:
The capacitance of a parallel plate capacitor is given by the following formula:
C = ε₀A/d
where,
C = Capacitance
ε₀ = Permeability of free space
A = Area of plates
d = Distance between plates
FOR CAPACITOR A:
C = CA = 17.8 nF = 17.8 x 10⁻⁹ F
A = A₁
d = d₁
Therefore,
CA = ε₀A₁/d₁ = 17.8 x 10⁻⁹ F ----------------- equation 1
FOR CAPACITOR B:
C = CB = ?
A = A₁/2
d = 2 d₁
Therefore,
CB = ε₀(A₁/2)/2d₁
CB = (1/4)(ε₀A₁/d₁)
using equation 1:
CB = (1/4)(17.8 X 10⁻⁹ F)
<u>CB = 4.45 x 10⁻⁹ F = 4.45 nF</u>
Galaxy-a collection of dust, gas, AND STARS. But I'm pretty positive this should be the answer.
Answer:
Explanation:
Height attained by body = 50 cm
= .5 m
Initial velocity = u
v² = u² - 2gh
0 = u² - 2gh
u² = 2 x 9.8 x .5
u = 3.13 m /s
During the initial period , the muscle stretches by around 10 cm during which force by ground reacts on the body and gives acceleration to achieve velocity of 3.13 m/s from zero .
v² = u² + 2as
3.13² = 0 + 2 a x .10
a = 49 m/s²
reaction by ground R
Net force
R-mg = ma
R= m ( g +a )
= mg + ma
=W + (W/g) x a
W ( 1 + a / g )
= W ( 1 + 49 / 9.8 )
= 6W
Answer:
4000 Hz
Explanation:
An anti-alias filter is usually added in front of the ADC to limit a certain range of input frequencies in order to avoid aliasing. This filter is usually a low pass filter that passes low frequencies but attenuates the high frequencies.
The Nyquist sampling criteria states that the sampling rate should be at least twice the maximum frequency component of the desired signal.
Sampling rate = 2(max input frequency)
From the relation we can find out the cut-off frequency for the anti-aliasing filter.
max input frequency = sampling rate/2
max input frequency = 8100/2 = 4050 Hz
Therefore, 4000 Hz would be an appropriate cut-off frequency for the anti-aliasing filter.
Answer:
Explanation:
<u>Given the following data;</u>
Initial velocity = 0 (since the stone is starting from rest).
Final velocity = 32 m/s
Acceleration = g = 10 m/s²
Time = 3.2 seconds
To show that the speed of the stone when it hits the ground is 32 m/s, we would use the first equation of motion;
Where;
- V is the final velocity.
- U is the initial velocity.
- a is the acceleration.
- t is the time measured in seconds.
Substituting into the formula, we have;
<em>Proven: 32 m/s = 32 m/s</em>
