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Degger [83]
3 years ago
11

Which of the following are possible rational roots of the polynomial function f(x)=5x^2-3x+3

Mathematics
2 answers:
yanalaym [24]3 years ago
7 0

You didn't post any option, but the ration roots theorem states that all possible rational roots of a polynomial come in the form

\pm\dfrac{p}{q}

where p divides the constant term and q divides the leading term of the polynomial. So, in your case, p divides 3 (i.e. it is 1 or 3), and q divides 5 (i.e. it is 1 or 5).

So, the possible roots are

\pm 1,\quad \pm 3,\quad \pm\dfrac{1}{5},\quad \pm\dfrac{3}{5}

For the record, this parabola has no real roots.

lapo4ka [179]3 years ago
6 0

Answer:

Step-by-step explanation:

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The line through (4,-1) and (k,5) is parallel to the line y=-3x+5. FInd the value of k.
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Answer:

k = 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 3x + 5 ← is in slope- intercept form

with slope m = - 3

Parallel lines have equal slopes, thus the 2 points have a slope of - 3

calculate the slope using the slope formula and equate to - 3

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (4, - 1) and (x₂, y₂ ) = (k, 5)

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k - 4 = - 2 ( add 4 to both sides )

k = 2

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3 years ago
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