You didn't post any option, but the ration roots theorem states that all possible rational roots of a polynomial come in the form
![\pm\dfrac{p}{q}](https://tex.z-dn.net/?f=%5Cpm%5Cdfrac%7Bp%7D%7Bq%7D)
where p divides the constant term and q divides the leading term of the polynomial. So, in your case, p divides 3 (i.e. it is 1 or 3), and q divides 5 (i.e. it is 1 or 5).
So, the possible roots are
![\pm 1,\quad \pm 3,\quad \pm\dfrac{1}{5},\quad \pm\dfrac{3}{5}](https://tex.z-dn.net/?f=%5Cpm%201%2C%5Cquad%20%5Cpm%203%2C%5Cquad%20%5Cpm%5Cdfrac%7B1%7D%7B5%7D%2C%5Cquad%20%5Cpm%5Cdfrac%7B3%7D%7B5%7D)
For the record, this parabola has no real roots.