For question 1) During the 8-9 , Mr hare travel 40miles For the time 9 onwards they travel concurrently, Let x be the distance covered by both since they can only meet if they covered the sams distance, x/50 = x/40 -1 ,where the 1 is the (8-9) 1 hr x/40 - x/50 = 1 x = 200 Time take by Mr Hare = 200/ 40 = 5 from 8 add 5 hours will be 1 ans is b 2) during 8- 9 hare travelled 50miles let x be the distance x/55= x/50-1 x/50-x/55=1 x=550miles time taken by hare = 550/50=11 hr ie when they first meet it will be 7pm so ans is b 8
