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musickatia [10]
3 years ago
5

How do I solve this step by step?

Mathematics
1 answer:
nevsk [136]3 years ago
3 0

Answer:

Step-by-step explanation:

i can't see the full equation

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4 years ago
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If f(x) and its inverse function,f-1(x), are both plotted on the same coordinate plane, where is their point of intersection?
Mice21 [21]
Consider f, such that f(x)=y, where x is in the Domain of f, and y is in the Range of f.

Let f(a)=b. So, (a, b) is in the graph of f.


The inverse function of f, f^{-1} (if exists) is such that  if f(x)=y, then f^{-1}(y)=x.

So if (a, b) is a particular point in the graph of f, then (b, a) is a point in the graph of  f^{-1}.

 
A point where they intersect is a point where (a, b)=(b, a), that is a=b. Among our choices, only (2, 2) satisfies this condition.


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4 years ago
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Last one for today !
RSB [31]
Easy

4 and 1/3+7 and 1/5=4+1/3+7+1/5=4+7+1/3+1/5=11+5/15+3/15=11+8/15=11 and 8/15

answer is D
4 0
3 years ago
Simplify 6 - 2(8x - 9) + 11x<br><br> 43x - 9<br> 43x - 36<br> -5x + 24<br> -5X - 3
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I hope this helps, have a great day!

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10. Your Turn: Find the equation of a line that is perpendicular to y=2x+7, and passes through the point (-4, 7). SHOW YOUR WORK
agasfer [191]
Alright, so since the slope of the perpendicular line is -1/(slope), we get (-1/2)=-1/2 and y=(-1/2)x + something. Plugging 7 in as y and -4 in as x, we get 7=(-1/2)(4)+something (let's make it a variable b), and multiplying it out we get 7=-2+b. Adding 2 to both sides, we get 7+2=9=b, so the perpendicular line equation is therefore y=(-1/2)x+b<span />
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3 years ago
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