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rodikova [14]
4 years ago
10

A poker hand consisting of 7 cards is dealt from a standard deck of 52 cards. Find the probability that the hand contains exactl

y 3 face cards. Leave your answer as a reduced fraction.
Mathematics
1 answer:
77julia77 [94]4 years ago
7 0

Answer:

The probability is 2,010,580/13,378,456

Step-by-step explanation:

Here is a combination problem.

We want to 7 cards from a total of 52.

The number of ways to do this is 52C7 ways.

Also, we know there are 12 face cards in a standard deck of cards.

So we are selecting 3 face cards from this total of 12.

So also the number of cards which are not face cards are 52-12 = 40 cards

Out of all these 40, we shall be selecting exactly 4. The number of ways to do this 40C4

Thus, the required probability will be;

(40C4 * 12C3)/52C7 = (91,390 * 220)/133,784,560

= 20,105,800/133,784,560 = 2,010,580/13,378,456

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Answer:

a is true and becomes complimentary as they both add up to 90 degree.

b. is true it is the only vertical angle group. As points AE, and BD cross and create these angles.

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Points 3, 4 as a group and 3,2,1 as a group and 2,1,5 as a group are each supplementary as each group add up to 180 degree. 1,5 on its own is not supplementary

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Points 3,5 become vertical angles as a group.

Angles A:B + D:E are also vertical angles this shows points 1,2 and 4 as a group of vertical angles.

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