All categories

3 years ago

Slope of (-4,7) (-6,-4)

Mathematics

2 answers:

Wittaler [7]3 years ago

7 0

Answer:

11/2

Step-by-step explanation:

We can use the formula, y2-y1/x2-x1. -4-7/-6+4=-11/-2=11/2

Yakvenalex [24]3 years ago

5 0

Answer:

m= 11/2

Step-by-step explanation:

You might be interested in

Hellllppppp me plssss

vodka [1.7K]

Answer:

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

trigonometry
equation
PEMDAS

<h3>tips and formulas:</h3>

$\sin( \theta) = \frac{opp}{hypo}$

<h3>given:</h3>

opp:7
hypo:10

<h3>let's solve:</h3>

$\sin( \theta) = \frac{7}{10}$

$\theta = asin( \frac{7}{10} )$

$\theta = 44.4^{o}$

8 0

3 years ago

A truck is carrying 6 cars weighing an average of 4,500 pounds each. What is the total weigh in tons of the cars on the truck?

yanalaym [24]

Answer:

Step-by-step explanation:

6 * 4500= 27000

7 0

3 years ago

Read 2 more answers

Last June only 0.17 inches of rain fell all month. What is the difference between the average rainfall and the actual rainfall f

spin [16.1K]

Answer:

Part 1) 0.50 inches

Part 2) 1.14 inches

Part 3)

a) 1.25 inches

b) -0.32 inches

Step-by-step explanation:

The complete question in the attached figure

Part 1) Last June only 0.17 inches of rain fell all month. What is the difference between the average rainfall and the actual rainfall for the last June

Let

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

The difference between the average rainfall and the actual rainfall for the last June is given by the expression

$(x-y)$

we have

$x=0.67\ in\\y=0.17\ in$

substitute

$0.67-0.17=0.50\ in$

Part 2) The departure from the average rainfall last July was -0.36 inches. How much rain fell last July?

we know that

The departure from the average is the difference between the actual amount of rain and the average amount of rain for a given month

Let

D -----> the departure from the average

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

$D=y-x$

we have

$D=-0.36\ in\\x=1.5\ in$

substitute the given values

$-0.36=y-1.5$

solve for y

$y=1.5-0.36\\y=1.14\ in$

Part 3)

<u>Part a)</u> How much rain would have to fall in August so that the total amount of rain equals the average rainfall for these three months?

<u>Part b</u>) What would the departure from the average be in August in that

situation?

Part a) How much rain would have to fall in August so that the total amount of rain equals the average rainfall for these three months?

Find the average rainfall for these three months

Adds the average rainfall and divide by 3

$(0.67+1.5+1.57)/3=1.25\ in$

Part b) What would the departure from the average be in August in that

situation?

we know that

The departure from the average is the difference between the actual amount of rain and the average amount of rain for a given month

Let

D -----> the departure from the average

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

$D=y-x$

we have

$x=1.57\ in\\y=1.25\ in$

substitute the given values

$D=1.25-1.57=-0.32\ in$

7 0

4 years ago

System II

dalvyx [7]

Answer:

<h2>hope it helps you see the attachment for further information </h2>

8 0

3 years ago

Does this sum converge: show steps

ehidna [41]

Answer:

Yes

Step-by-step explanation:

$\sum_{n=1}^{\infty} e^{-\sqrt{n} } \\\sum_{n=1}^{\infty} (\frac{1}{e})^{\sqrt{n} }$

If we say u = √n, then:

$\sum_{u=1}^{\infty} (\frac{1}{e})^{u}$

This is a geometric series. Since |1/e| < 1, the series converges.

6 0

4 years ago

Slope of (-4,7) (-6,-4)​

Slope of (-4,7) (-6,-4)