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Igoryamba
3 years ago
7

Expression A Expression B Expression C (−5)(−0.4)(1.8) (-45)(-19)(-112) −1(5+17) Expression D Expression E Expression F (−5)(−0.

4)(1.8)(−3.25) (-49)(-34)(-12)(-12) −1(3.5−7) How many expressions will have a product that is positive?
Mathematics
1 answer:
kramer3 years ago
4 0

Answer:

Expressions A, E, and F

Step-by-step explanation:

In general, when negative integers are multiplied; if the negative integers are even, then the product would be positive. But if the negative integers are odd, then the product would be negative.

Thus,

A. (−5)(−0.4)(1.8) = (2.0)(1.8)

                           = 3.6

B. (-45)(-19)(-112) = (855)(-112)

                           = -95760

C. −1(5+17) = -1(22)

                 = -22

D. (−5)(−0.4)(1.8)(−3.25) = (2.0)(-5.85)

                                      = -11.7

E. (-49)(-34)(-12)(-12) = (1666)(144)

                                = 239904

F. −1(3.5−7) = -1(-3.5)

                  = 3.5

Thus expressions A, E and F have positive products.

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Consider the equation

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It is easy to see that x=20 is a solution of this equation, because when x=20:

\dfrac{1}{4}x-5=\dfrac{1}{4}\cdot 20-5=5-5=0,

\dfrac{x-20}{3}=\dfrac{20-20}{3}=\dfrac{0}{3}=0.

Also this equation have:

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2. a fractional coefficient on the left side;

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Imran deposited 3000 per month (at the start of month) into a saving account for 10 months. If the bank offer 6% interest compou
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Answer:

3.590.04

Step-by-step explanation:

The formula given for total amount saved when compounding interest =

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P = 3000

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t = 3 years

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4 years ago
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5 0
3 years ago
Find four distinct complex numbers (which are neither purely imaginary nor purely real) such that each has an absolute value of
Luda [366]

Answer:

  • 0.5 + 2.985i
  • 1 + 2.828i
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Explanation:

Complex numbers have the general form a + bi, where a is the real part and b is the imaginary part.

Since, the numbers are neither purely imaginary nor purely real a ≠ 0 and b ≠ 0.

The absolute value of a complex number is its distance to the origin (0,0), so you use Pythagorean theorem to calculate the absolute value. Calling it |C|, that is:

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Then, the work consists in finding pairs (a,b) for which:

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You can do it by setting any arbitrary value less than 3 to a or b and solving for the other:

\sqrt{a^2+b^2}=3\\ \\ a^2+b^2=3^2\\ \\ a^2=9-b^2\\ \\ a=\sqrt{9-b^2}

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b=0.5;a=\sqrt{9-0.5^2}=2.958\\ \\b=1;a=\sqrt{9-1^2}=2.828\\ \\b=1.5;a=\sqrt{9-1.5^2}=2.598\\ \\b=2;a=\sqrt{9-2^2}=2.236

Then, four distinct complex numbers that have an absolute value of 3 are:

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  • 2 + 2.236i
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